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Alexandra [31]
3 years ago
9

Pls help me!!!!

Chemistry
2 answers:
Elza [17]3 years ago
8 0

Answer:

Cacti and Sage Brush

Explanation:

because they are plants so they produce food on their own

777dan777 [17]3 years ago
5 0

Answer:

C since both are plants which are the producers

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How heat moves from one end of a solid to another
pantera1 [17]
In conduction, the thermal energy of a particle is transferred to other particles throughout the solid. The particles with more energy are transferred to those with less.
3 0
4 years ago
Name the three functional groups in the compound pictured.
oksian1 [2.3K]

The three functional groups shown in the image are: ester, alkoxy and carboxyl.

<h3>What are functional groups?</h3>

Chemical properties depend on its structure. Certain properties, too, are attributable to an atomic group ordered in a particular way, apart from the whole of the molecule. Such groups of atoms that determine the chemical properties of compounds are called<em> functional groups</em>.

The functional group can be on the primary, secondary, or tertiary carbon.

Functional groups are often found on molecules of biological importance.

Functional groups are usually formed by a set of elements such as carbon, hydrogen and oxygen, attached to the hydrocarbon chain, giving the molecule characteristics. Can also include other elements such as sulfur or nitrogen.

Molecules can have more than one functional group on it, having different combinations on it that can affect properties of the molecule such as solubility, structure, or reactivity.

Carboxyl groups are usually seen in amino acids, fatty acids and other molecules since it is a fairly common functional group.

Therefore, we can confirm that the three functional groups shown in the image are: ester, alkoxy and carboxyl.

To learn more about functional groups visit: brainly.com/question/14618322?referrer=searchResults

#SPJ1

8 0
2 years ago
Fe(s) + S(s) → FeS(s)
insens350 [35]

The mass of FeS formed : 11.97 g

<h3>Further explanation</h3>

Reaction

Fe(s) + S(s) → FeS(s)

mass Fe=7.62 g

mol Fe(MW=56 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{7.62}{56}\\\\mol=0.136

mass S=8.67 g

mol S(MW=32 g/mol) :

\tt mol=\dfrac{8.67}{32}=0.271

Limiting reactant : smaller ratio(mol:coefficient) ⇒coefficient=1

Fe : S =0.136 : 0.271⇒Fe limiting(smaller), S excess

Mol FeS based on Fe , so mol FeS=0.136

Mass FeS(MW=88 g/mol) :

\tt mass=mol\times MW\\\\mass=0.136\times 88=11.97~g

5 0
3 years ago
Equivalent massof sodium​
andre [41]

Answer:

Sodium

Formula : Na

Equivalent mass:23.0

Mark me as Branliest

8 0
3 years ago
Which of the following is least likely to increase the rate of diffusion?A small concentration gradientB higher concentration of
Ksenya-84 [330]

Answer: Option (A) is the correct answer.

Explanation:

Rate of diffusion is defined as the total movement of molecules from a region of higher concentration to lower concentration.

The interaction between medium and the material is responsible for the rate of diffusion of a material or substance.

A small concentration gradient means small difference in the number of molecules taking part in a reaction. So, when there no large difference between the concentration then there won't be much difference in the rate of diffusion of a material.

Whereas a higher concentration of molecules will lead to more number of collisions due to which frequency of molecules increases. Therefore, rate of diffusion will also increase.

Small molecule size will also lead to increases in rate of diffusion. This is because according to Graham's law rate of diffusion is inversely proportional to molar mass of an element. Hence, smaller size molecule will have smaller mass. As a result, rate of diffusion will be more.

High temperature means more kinetic energy of molecules due to which more number of collisions will be there. Hence, rate of diffusion will also increase.

Thus, we can conclude that out of the given options a small concentration gradient  is least likely to increase the rate of diffusion.

4 0
3 years ago
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