Answer:
You will be able to watch the slow dissolution of the nail (probably a steel nail and not iron) and the change in colour of the solution.
Explanation:
I believe not 100% sure.
Answer:
C = 9460 Kj
Explanation:
Given data:
Mass of copper = 2kg
Latent heat of vaporization = 4730 Kj/Kg
Energy required to vaporize 2kg copper = ?
Solution:
Equation
Q= mLvap
by putting values,
Q= 2kg × 4730 Kj/Kg
Q = 9460 Kj
<span>Answer: option (1) solubility of the solution increases.
</span><span />
<span>Justification:
</span><span />
<span>The solubility of substances in a given solvent is temperature dependent.
</span><span />
<span>The most common behavior of the solubility of salts in water is that the solubiilty increases as the temperature increase.
</span><span />
<span>To predict with certainty the solubility at different temperatures you need the product solubility constants (Kps), which is a constant of equlibrium of the dissolution of a ionic compound slightly soluble in water, or a chart (usually experimental chart) showing the solubilities at different temperatures.
</span><span />
<span>KClO₃ is a highly soluble in water, so you do not work with Kps.
</span><span />
<span>You need the solubility chart or just assume that it has the normal behavior of the most common salts. You might know from ordinary experience that you can dissolve more sodium chloride (table salt) in water when the water is hot. That is the same with KClO₃.
</span><span>The solubility chart of KlO₃ is almost a straight line (slightly curved upward), with positive slope (ascending from left to right) meaning that the higher the temperature the more the amount of salt that can be dissolved.</span>
This problem is providing the mass, energy, initial temperature and specific heat of a sample of copper that is required to calculate the final temperature.
Thus, we recall the general heat equation:

Which has to be solved for the final temperature,
as follows:

Finally, we plug in the numbers to obtain:

However, this result is not given in the choices.
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