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Semmy [17]
2 years ago
9

Balance the following reaction. A.) 4 B.) 2 C.) 5 D.) blank E.) 3

Chemistry
1 answer:
slega [8]2 years ago
7 0

Answer:

C.5

Hope this helps

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2 Fluorine atoms covalently bonded with each other, each sharing an equal number of a single, one valence electron to achieve a stable octet, would form a diatonic fluorine gas. It is a diatomic molecule, a molecule consisting of 2 atoms that are the same, in this case fluorine.
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2 years ago
Calculating the volume of 0.05mol/dm3 KOH is required to neutralise 25.0cm3 of 0.0150mol/dm3 HNO3
kvasek [131]

Answer:

You first need to construct a balanced chemical equation to describe the reaction:

KOH + HNO3 ---------> KNO3 + H2O

Work out the no. moles of HNO3 being neutralized:

Moles = Volume x Concentration = (25/1000) x 0.0150 = 0.000375 moles

From the balanced equation the molar ratio of KOH to HNO3 is 1:1 so you also need 0.000375 moles of KOH to neutralise the nitric acid

Now you can work out the volume of KOH required:

Volume = Moles/Concentration = (0.000375)/0.05 = 0.0075 dm^3 = 7.5 cm^3

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Atoms are bound together into collections called molecules, compounds, ions, and other types of groups. Which of these is classi
Nonamiya [84]
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Help ill give brainliest need help with number 8
kotegsom [21]

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the sun goes away and takes heat with it

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Read 2 more answers
The decomposition of NH4HS is endothermic: NH4HS(s)⇌NH3(g)+H2S(g) Part A Which change to an equilibrium mixture of this reaction
shepuryov [24]

Explanation:

According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.

As the given reaction is as follows.

       NH_{4}HS(s) \rightleftharpoons NH_{3}(g) + H_{2}S(g)

(a)  When increase the temperature of the reactants or system then equilibrium will shift in forward direction where there is less temperature. It is possible for an endothermic reaction.

Thus, formation of H_{2}S will increase.

  • (b)  When we decrease the volume (at constant temperature) of given reaction mixture then it implies that there will be increase in pressure of the system. So, equilibrium will shift in a direction where there will be decrease in composition of gaseous phase. That is, in the backward direction reaction will shift.

Hence, formation of H_{2}S will decrease with decrease in volume.

  • When we increase the mount of NH_{4}HS then equilibrium will shift in the direction of decrease in concentration that is, in the forward direction.

Thus, we can conclude that formation of H_{2}S will increase then.

3 0
3 years ago
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