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Sindrei [870]
3 years ago
9

Area of the rectangle is given by the polynomial function A(x)=2x^2+18x. If the width of the rectangle is 2x what is the length?

Mathematics
1 answer:
Allushta [10]3 years ago
7 0

Answer:

x + 9

Step-by-step explanation:

Area = 2x^2 + 18x

Width = 2x

Length = ?

The relationship between these quantities is;

Area = Length * Width

Length = Area / Width

Length = (2x^2 + 18x) / 2x

Using long division;

2x\sqrt{2x^{2}  + 18x}

This leads to;

length = x + 9

Checking;

Area = Length * Width

Area = (x + 9) * 2x

Area = 2x^2 + 18x ; This is correct!

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Mrrafil [7]

<u>Answer:</u>

Nickels = 44.6

Dimes = 3.4

<u>Step-by-step explanation:</u>

We know that Jessica has 48 coins of which some are nickels and some are dimes so we can write it as:

n = amount of nickels

d = amount of dimes

n+d=48 --- (1)

We are to find the number of nickels and dimes if their total worth is $3.25.

Since a dime is worth 10¢ and a nickel is 5¢, so it should be:

0.05n + 0.3d = 3.25 --- (2)

From (1):

n=48-d

Substituting this value of n in (2) to get:

0.05(48-d) + 0.3d = 3.25

2.4-0.05d+0.3d=3.25

2.4+0.25d=3.25

0.25d=0.85

d=3.4

Finding n by substituting the value of d:

n=48-d

n=48-3.4

n=44.6

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