<img src="https://tex.z-dn.net/?f=%5Csqrt%7B200%5C%5C" id="TexFormula1" title="\sqrt{200\\" alt="\sqrt{200\\" align="absmiddle"

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Inga [223]

3 years ago

class="latex-formula">

Mathematics

2 answers:

maks197457 [2]3 years ago

7 0

Answer: 14.1421356237

Step-by-step explanation: We should know that 200 can be written in radical form (√200 = q × q = q2). To find the square root of 200, first you can ask yourself whether √200 is a perfect square, in which it isn’t because it doesn’t equal a whole number. Next, ask yourself if √200 is a rational or irrational number, in which it is an irrational number. After, determine whether √200 can be simplified, which in this case can be simplified to 200 = 10√2 which makes it easier to calculate the square root of 200. Lastly, the easiest and most boring way to calculate the square root of 200 is to use your calculator! Simply type in 200 followed by √x to get the answer. We did that with our calculator and got the following answer with 9 decimal numbers:

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Yuri [45]3 years ago

4 0

Do sqrt(100) * sqrt(2)
Which will be 10 * sqrt(2)

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Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2

fredd [130]

Answer:

Both get the same results that is,

$\left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

Step-by-step explanation:

Given :

$\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]$

and initial population,

$\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]$

a) - After two times, we will find in each position.

$P_2=[P].[M]^2=[P].[M].[M]$

$M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]$

$=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]$

$\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]$