<span>In this item, we are asked to calculate for the mass of 22.05 mole of octane given that its molecular mass is equal to 114.22 g/mol. To answer this item, we simply have to multiply the number of moles with the molecular mass. That is, (114.22 g/mol)(22.05 mol) which is equal to 2518.221 grams. </span>
Answer:
The answer to this question is; <em>1.08 x 10^5</em>
Explanation:
This is the correct option because
600 x 180 = 108,000
108,000. -> move the decimal over 5 times to get a number between 1 and 10
1.08 x 10^5
The red diamond tells how flammable the chemical compound is or how easily it catches fire.
The yellow diamond tells about reactivity how quickly the compound reacts with other materials.
Answer:
B) the electron
Explanation:
JJ Thompson discovered the model for electron
<span>1) Balanced chemical equation
Sb2S3(s) + 3Fe(s) --> 2Sb(s) + 3FeS(s)
2) Theoretical molar ratios
1 mol SbsS3 : 3 mol Fe : 2 mol Sb : 3 mol FeS
3) Convert </span><span>18.45g Sb2S3 and12.1g Sb to moles
You need to use the atomic and molar masses
Sb: 121.76 g/mol
S: 32.07 g/mol
Sb2S3: 2 * 121.76 g/mol + 3 * 32.07 g/mol = 339.73 g/mol
18.45 g Sb2S3 / 339.73 g/mol = 0.0543 mol Sb2S3
12.1 g Sb / 121.76 g / mol = 0.099 mol Sb
Theoretical yield:
1 mol Sb2S3 / 2 mol Sb = 0.0543 mol SbsS3 / x mol Sb
Solve for x:
x = 0.0543 mol Sb2S3 * 2 mol Sb / 1 mol Sb2S3 = 0.1086 mol Sb
4) Percent yield
0.099 mol Sb / 0.1086 mol Sb * 100 = 91.16%
Answer: 91.5% (the difference with 91.16% is due to the decimals used for the atomic masses)
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