The structure of n‑methyl‑2‑pyrrolidone when it is heated with aqueous acid. product is given below
<h3 /><h3>What is aprotic solvent?</h3>
A polar solvent without an acidic proton is known as a polar aprotic solvent. These solvents don't include hydroxyl or amine groups. These solvents can act as proton acceptors, but unlike protic solvents, they do not act as proton donors in hydrogen bonding.
After being exposed to a strong aqueous acidic media and being heated, N-methyl-2-pyrrolidone opens up, forming a molecule with a carboxylic group at one end and a protonated nitrogen atom with a methyl group connected to it at the other.
Alcohol, water, hydrogen fluoride, formic acid, acetic acid, ammonia, methanol, ethanol, and other well-known substances are a few examples of polar protic solvents. Polar aprotic solvents, on the other hand, lack acidic protons and do not function as donors during hydrogen bonding.
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Answer:
More Energy
Explanation:
Energy is required to break bonds
Answer:
The balanced chemical equation: NH₃ + 2 HF → NH₄⁺ + HF₂⁻
Explanation:
According to the Brønsted–Lowry acid–base theory, the acid- base reaction is a type of chemical reaction between the acid and base to give a conjugate acid and a conjugate base.
In this reaction, a Brønsted–Lowry acid loses a proton to form a conjugate base. Whereas, a Brønsted–Lowry base accepts a proton to form a conjugate acid.
Acid + Base ⇌ Conjugate Base + Conjugate Acid
The acid dissociation constant (Kₐ) <em>signifies the acidic strength of a chemical species.</em>
∵ pKₐ = - log Kₐ
Thus for a strong acid, Kₐ value is large and pKₐ value is small.
pKₐ (HF) = 3.2 → strong acid
pKₐ (NH₃) = 38 → weak acid
<u>The chemical reaction involved in the dissolution process:</u>
NH₃ + 2 HF → NH₄⁺ + HF₂⁻
In this acid-base reaction, the acid HF reacts with NH₃ base to give the conjugate base HF₂⁻ and conjugate acid NH₄⁺.
<u>HF (acid) donates a proton to form the conjugate base, HF₂⁻ ion. NH₃ (base) accepts a proton to form the conjugate acid. </u>
The original question is to find the pH and the pOH of 0.023 M of perchloric acid.
Answer:
pH = 1.638
pOH = 12.362
Explanation:
1- getting the pH:
pH can be calculated using the following rule:
pH = -log[H+]
Since the given solution is an acid, this means that [H+] is the same as the concentration of the solution.
This means that:
[H+] = 0.023
Substitute in the above equation to get the pH as follows:
pH = -log[0.023]
pH = 1.638
2- getting the pOH:
We know that:
pH + pOH = 14
We have calculated that pH = 1.638.
Substitute in the above equation to get the pOH as follows:
pOH + 1.638 = 14
pOH = 14 - 1.638
pOH = 12.362
Hope this helps :)
Answer:
Practice good personal hygiene. Wash your hands after removing gloves, before leaving the laboratory, and after handling a potentially hazardous material. While working in the laboratory, wear personal protective equipment - eye protection, gloves, laboratory coat - as directed by your supervisor.
Explanation:
