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Novay_Z [31]
3 years ago
11

What is the concentration of nitrate ion in a 425 mL solution containing 32.0 g of Mg(NO3)2 (M = 148.3)?

Chemistry
1 answer:
Butoxors [25]3 years ago
6 0
Mg(NO3)2 ➡️ Mg2+ + 2 NO3-

(32.0g Mg(NO3)2) / (148.3g Mg(NO3)2/mol)* (2 mol NO3- / 1 mol Mg(NO3)2) / (0.425 L) = 1.02 mol/ L NO3-
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A 4.0 L container holds a sample of hydrogen gas at 306 K and 150 kPa. If the pressure increases to 300 kPa and the volume remai
riadik2000 [5.3K]

Answer:

612 K

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 306 K

Initial pressure (P₁) = 150 kPa

Final pressure (P₂) = 300 kPa

Volume = 4 L = constant

Final temperature (T₂) =?

Since the volume is constant, the final (i.e the new) temperature of the gas can be obtained as follow:

P₁ / T₁ = P₂ / T₂

150 / 306 = 300 / T₂

Cross multiply

150 × T₂ = 306 × 300

150 × T₂ = 91800

Divide both side by 150

T₂ = 91800 / 150

T₂ = 612 K

Thus, the new temperature of the gas is 612 K

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oksian1 [2.3K]

Answer:

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Explanation:

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Why is most of the Earth’s fresh water unavailable?
lisov135 [29]

Answer:

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When aluminum, Al, metal is dipped in an aqueous solution of hydrochloric acid, HCl, hydrogen gas, H2, is produced with the form
Nataliya [291]

Answer:

Al(s) + 3HCl(aq) → AlCl₃(aq) + 3/2H₂(g).

Explanation:

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So, the balanced equation is:

<em>Al(s) + 3HCl(aq) → AlCl₃(aq) + 3/2H₂(g).</em>

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