Fe+CuSO4⟶Cu+FeSO4
Given that
FeSO4 = 92.50 g
Number of moles = amount in g / molar mass
=92.50 g / 151.908 g/mol
=0.609 moles FeSO4
Now calculate the moles of CuSO4 as follows:
0.609 moles FeSO4 * 1 mole CuSO4 /1 mole FeSO4
= 0.609 moles CuSO4
Amount in g = number of moles * molar mass
= 0.609 moles CuSO4 * 159.609 g/mol
= 97.19 g CuSO4
CH3-CH=CH-CH2-CH3 <--------CH3-CH2-CHCl-CH2_CH3
3-Cl-pentane , 3-Hal-pentane
Answer:
6.022 x 1023 molecules = 1 Mole O2 = 22.4L
3.022 x 1023 molecules = 1/2 Mole O2 = 11.2L
The answer is 11.2 Litres
Explanation:
Its 4.08 i hope hopefully its helpful
Answer:
b. cost to implement conservation policies
Explanation:
