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posledela
2 years ago
12

One fourth of marked price of a watch is given as discount. What is the discount percent​

Mathematics
1 answer:
kumpel [21]2 years ago
4 0

Answer:

pretty sure its 25%

Step-by-step explanation:

1/4 is the same as 0.25 which is also the same as 25%

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at the ring toss booth in a carnival 8 people lost and forty people won. how many times as many people won as lost?
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32 people won as lost
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A particular security's default risk premium is 2 percent. for all securities, the inflation risk premium is 1.75 percent and th
larisa [96]
To solve this problem and calculate the security's equilibrium rate of return, you should sum<span> the security's default risk premium (2.00%),</span> the inflation risk premium (1.75%), the real risk-free rate (3.50%), the security's liquidity risk<span> premium (0.25%) </span><span>and the maturity risk premium (0.85%). So, you have:
 
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3 years ago
How do I do phythagoras theorem?
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Answer:

Step-by-step explanation:

To do pythagoras theorem

You apply the rules

Which state that,in right angled triangle the square of hypotenus is equal to sum of the square of the other two side. That is

hyp^2=opp^2+adj^2

7 0
3 years ago
Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a
spin [16.1K]

Answer:

Mean = 68.9

s^2 =18.1 --- Variance

Step-by-step explanation:

Given

\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5

For 59 - 66

x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5

For 67 - 74

x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5

For 75 - 82

x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5

For 83 - 90

x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5

So, the table becomes:

\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

The mean is then calculated as:

Mean = \frac{\sum fx}{\sum f}

Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}

Mean = \frac{2547.5}{37}

Mean = 68.9 -- approximated

Solving (b): The sample variance:

This is calculated as:

s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}

So, we have:

s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}

s^2 =\frac{652.8}{36}

s^2 =18.1 -- approximated

5 0
2 years ago
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