A box sits on a table. A long arrow labeled F subscript P = 22 N points right. A short arrow labeled F subscript f = ? N points
left. A man pushes on the box from the left. The net force acting on the box is 18 N. What is the force of friction?
–22 N
–4 N
4 N
22 N
–22 N
–4 N
4 N
22 N
2 answers:
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Answer:
(a)
Average velocity = < 0, 316000, 146000> m/s
(b) < 0, 2.844, 1.314 > m
Explanation:
r1 = < 0.02, 0.04, - 0.06 > m
r2 = < 0.02, 1.62, - 0.79 > m
time, t = 5 micro second = 5 x 10^-6 s
(a) Average velocity is defined as the ratio of total displacement to the total time taken.
Displacement = r = r2 - r1
r = < 0.02 - 0.02, 1.62 - 0.04, - 0.79 + 0.06 > m
r = < 0, 1.58, - 0.73 > m
So. Average velocity =
Average velocity =
Average velocity = < 0, 316000, 146000> m/s
(b)
Distance = velocity x time
Here time, t = 9 micro second
d = < 0, 316000, 146000> x 9 x 10^-6 m
d = < 0, 2.844, 1.314 > m
<u>Answer:</u>
The height of ramp = 124.694 m
<u>Explanation:</u>
Using second equation of motion,
From the question,
u = 31 m/s; s = 156.3 m, a=0
substituting values
t =
= 5.042 s
Similary, for the case of landing
t = 5.042 s; initial velocity, u =0
acceleration = acceleration due to gravity, g = 9.81
Substituting in
h = 124.694 m
So height of ramp = 124.694 m