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Scorpion4ik [409]
3 years ago
5

In the hydrologic cycle, water from the ocean ______ into the atmosphere where it can ______ and change back into tiny water dro

plets.
Blank #1: evaporates, precipitates, transpires, or condenses

Blank #2: precipitate, transpire, condense, or evaporate
Physics
2 answers:
SIZIF [17.4K]3 years ago
8 0
<h3 />

#1. Evaporates

#2. Condenses

In the hydrologic cycle, water from the ocean into the atmosphere where it can and change back into tiny water droplets.

<h3 />
allochka39001 [22]3 years ago
7 0
Blank 1,,is evaporates blank2,,,is condenses
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A 2 kg ball with an initial velocity of 10 m/s moves at an angle 60º above the +x-direction. The ball hits a vertical wall and b
kow [346]

Answer:

I = 20 i ^ N s

Explanation:

For this problem let's use the Impulse equation

       I = Δp = m v_{f}- v₀

The impulse and the velocity are vector quantities, let's calculate on each axis, let's decompose the velocity

     cos 60 = vₓ / v

     vₓ = v cos 60

     sin60 = v_{y} / v

     v_{y} = v sin60

     vₓ = 10 cos 60

     v_{y} = 10 sin60

    vₓ = 5.0 m / s

    v_{y} = 8.66 m / s

Let's calculate the impulse on each axis

X axis

     Iₓ = m v_{xf} - m vₓ₀

How the ball bounces

    v_{xf} = - vₓ₀ = vₓ

    Iₓ = 2 m vₓ

    Iₓ = 2 2 5

    Iₓ = 20 N s

Y axis

   I_{y} = m v_{yf} - m vyo

On the axis and the ball does not change direction so

   v_{yf} = vyo

  I_{y} = 0

The total momentum is

   I = Iₓ i ^ + I_{y} j ^

   I = 20 i ^ N s

7 0
3 years ago
How high off the ground is a 5.5 kg object that has a gravitational potential energy of 8500 DE=mah​
umka21 [38]

Answer:

h = 157.70 meters

Explanation:

Given the following data;

Mass = 5.5 kg

Gravitational potential energy = 8500 Joules

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the height of the object;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Substituting into the formula, we have;

8500 = 5.5*9.8*h

8500 = 53.9h

h = 8500/53.9

h = 157.70 m

7 0
3 years ago
The coefficent of static friction between the floor of a truck and a box resting on it is 0.38. The truck is traveling at 87.9 k
nekit [7.7K]

Answer:

d=79.9m

Explanation:

From the question we are told that:

coefficient of static friction \mu=0.38

Velocity v=87.9=>24.41667m/s

Generally the equation for Conservation of energy is mathematically given by

 \mu*mgd = 0.5 m v^2

 d=\frac{0.5*24.42^2}{0.38*9.8}

 d=79.9m

3 0
3 years ago
Rusty Pickins, a gold miner, has just found a chunk of gold. Rusty would like to change the gold from a solid to a liquid, so th
Vitek1552 [10]
<span>b.) Add heat to increase the molecular motion of the atoms</span>
5 0
4 years ago
8. An ant on a picnic table travels 30 cm eastward, then 25 cm northward, and finally 15 cm westward. What is the ant's displace
wel

Answer:

The displacement of the ant, R = 29.15 cm

The angle of the resultant displacement with its original position is, θ = 30° 57'

The direction of the displacement is towards the northeast.  

Explanation:

Given data,

The displacement towards east, d₁ = 30 cm

The displacement towards north, d₂ = 25 cm

The displacement towards  west, d₃ = 15 cm

The total displacement towards east,

                                       d₄ = d₁ - d₃

                                           = 30 - 15

                                           = 15 cm

The total displacement of ant is given by the resultant displacement,

                            R = √(d₂² + d₄² + 2· d₂ d₄ CosФ)

Where Ф is the angle between the vectors, d₂ & d₄

                                                Ф = 90°

Therefore,

                               R = √(d₂² + d₄²)

Substituting in the above equation,

                               R = √(25² + 15²)

                                  = 29.15 cm

Hence, the displacement of the ant, R = 29.15 cm

The angle of the resultant displacement with its original position is,

                                θ = tan⁻¹ (d₄ / d₂)

                                   = tan⁻¹ (15 / 25)

                                   = tan⁻¹ 0.6

                                   = 30° 57'

Hence, the angle of the resultant displacement the its original position is, θ = 30° 57'

The direction of the displacement is towards the northeast.                                            

5 0
4 years ago
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