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Alenkasestr [34]
2 years ago
8

In the image below, a free-body diagram represents the forces of several vehicles driving across a bridge. Assume that the bridg

e is in statio equilibrium and that it has zero weight, and solve for the unknown reaction force
A. 10,800 N
B. 65,200 N
C. 120,200 N
D. 53,400 N​

Physics
1 answer:
Ainat [17]2 years ago
6 0

Answer:

The answer is "57,400 N".

Explanation:

\Sigma F_y=0 \ \ \ \ \ \ \text{static equilibrium}\\\\\to 121,200+R=17800+150,000+10800\\\\R=57,400\ N

The answer is 57,400 N because the choices are wrong.

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Andy has two strong magnetic marbles of equal size. What will happen when he puts the two marbles about 2 centimeters apart?
VikaD [51]
I believe it would be C
5 0
3 years ago
Read 2 more answers
ASAP pls answer right and I will mark brainiest
Ronch [10]
1. D:Asteroids have geological activity
2.A:Short-period comets circle around the sun in 200 years or less and originate in the Kuiper Belt
3.D:All of the above
4.A:It’s gravity is too weak to clear it’s orbit
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I hope this helps
6 0
2 years ago
Physics Question (attached)
hammer [34]

Answer:

The answer is "\bold{10.6 \ \ \frac{m}{s^2}}"

Explanation:

The  Formula of acceleration:

\bold{a= \frac{v-v_0}{t}}

Given value:

t= 50\\v= 856\\v_0= 324

Calculating the acceleration:

\to  a = \frac{(856 - 324)}{50}\\\\

       = \frac{(532)}{50}\\\\= \frac{(106.4)}{10}\\\\= 10.64 \ \ \frac{ m}{s^2}

8 0
3 years ago
What happens to the pressure in all parts of a confined fluid if the pressure in one part is increased? The pressure in the othe
maw [93]

Answer:

option C

Explanation:

the correct answer is option C

When in a confined fluid the pressure is increased in one part than the pressure will equally distribute in the whole system.

According to Pascal's law when pressure is increased in the confined system then the pressure will equally transfer in the whole system.  

This law's application is used in machines like hydraulic jacks.

5 0
2 years ago
On the surface of planet y, which has a mass of 4.83x1024 kg, a 30.0 kg object weighs 50.0 n. what is the radius of the planet?
Aleksandr [31]
We can solve the problem in two steps:

1) From the weight W=50.0 N of the object, we can find the value of the gravitational acceleration g of the planet. In fact, the weight is equal to
W=mg
where m=30 kg is the mass of the object. From this, we find g:
g= \frac{W}{m}= \frac{50.0 N}{30 kg}=1.67 m/s^2

2) The gravitational acceleration of a planet with mass M and radius r is given by
g= \frac{GM}{r^2}
where G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational  constant. In our problem, the mass of the planet is 
M=4.83 \cdot 10^{24} kg, and we found g in step 1), g=1.67 m/s^2, so we have everything to solve and find the value of the radius r:
r= \sqrt{ \frac{GM}{g} }= \sqrt{ \frac{(6.67\cdot 10^{-11})(4.83 \cdot 10^{24})}{1.67} }=1.39\cdot 10^7 m
5 0
3 years ago
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