1 N to the right as shown on photo
In the image below, a free-body diagram represents the forces of several vehicles driving across a bridge. Assume that the bridg
e is in statio equilibrium and that it has zero weight, and solve for the unknown reaction force
A. 10,800 N
B. 65,200 N
C. 120,200 N
D. 53,400 N
A. 10,800 N
B. 65,200 N
C. 120,200 N
D. 53,400 N
1 answer:
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Answer:
3.24 m/s
Explanation:
Suppose that the boat sails with velocity (relative to water) direction being perpendicular to water stream. Had there been no water flow, it would have ended up 0m downstream
Therefore, the river speed is the one that push the boat 662 m downstream within 539 seconds. We can use this to calculate its magnitude
So the boat velocity vector relative to the bank is the sum of of the boat velocity vector relative to the water and the water velocity vector relative to the bank. Since these 2 component vectors are perpendicular to each other, the magnitude of the total vector can be calculated using Pythagorean formula:
m/s
Answer:
The second option.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
Explanation:
The first figure that I copy here with is the figure corresponding to this question.
The thumb is pointing upward.
The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.
The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.
So, the conclusion is that the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.
The second option.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
Explanation:
The first figure that I copy here with is the figure corresponding to this question.
The thumb is pointing upward.
The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.
The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.
So, the conclusion is that the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.