Ask question

Ask question

All categories

Alenkasestr [34]

3 years ago

8

In the image below, a free-body diagram represents the forces of several vehicles driving across a bridge. Assume that the bridg

e is in statio equilibrium and that it has zero weight, and solve for the unknown reaction force
A. 10,800 N
B. 65,200 N
C. 120,200 N
D. 53,400 N

1 answer:

Ainat [17]3 years ago

6 0

Answer:

The answer is "57,400 N".

Explanation:

$\Sigma F_y=0 \ \ \ \ \ \ \text{static equilibrium}\\\\\to 121,200+R=17800+150,000+10800\\\\R=57,400\ N$

The answer is 57,400 N because the choices are wrong.

You might be interested in

What two main gasses are exchanged during the process of breathing??

Zina [86]

Oxygen and carbon dioxide

4 0

3 years ago

Help asapp!!!!!!!!!!!!!!

IRINA_888 [86]

Sorry don’t know this one

3 0

3 years ago

The girl makes a microscope with a 3.0 cm focal length objective and a 5.0 cm eyepiece. The microscope tube length is 10 cm. Use

saul85 [17]

To solve this problem we will use the concepts related to Magnification. Magnification is the process of enlarging the apparent size, not physical size, of something. This enlargement is quantified by a calculated number also called "magnification".

The overall magnification of microscope is

$M = \frac{Nl}{f_ef_0}$

Where

N = Near point

l = distance between the object lens and eye lens

$f_0$ = Focal length

$f_e$ = Focal of eyepiece

Given that the minimum distance at which the eye is able to focus is about 25cm we have that N = 25cm

Replacing,

$M = \frac{25*10}{3*5}$

$M = 16.67\approx 17\\$

Therefore the correct answer is C.

3 0

3 years ago

12. A rocket, initially at rest on the ground, accelerates vertically. It accelerates uniformly until it

vodomira [7]

Answer:

We kindly invite you to read carefully the explanation and check the image attached below.

Explanation:

According to this problem, the rocket is accelerated uniformly due to thrust during 30 seconds and after that is decelerated due to gravity. The velocity as function of initial velocity, acceleration and time is:

$v_{f} = v_{o}+a\cdot (t-t_{o})$ (1)

Where:

$v_{o}$ - Initial velocity, measured in meters per second.

$v_{f}$ - Final velocity, measured in meters per second.

$a$ - Acceleration, measured in meters per square second.

$t_{o}$ - Initial time, measured in seconds.

$t$ - Final time, measured in seconds.

Now we obtain the kinematic equations for thrust and free fall stages:

Thrust ( $v_{o} = 0\,\frac{m}{s}$ , $a = 30\,\frac{m}{s^{2}}$ , $t_{o} = 0\,s$ , $0\,s\le t< 30\,s$ )

$v = 30\cdot t$ (2)

Free fall ( $v_{o} = 900\,\frac{m}{s}$ , $a = -9.807\,\frac{m}{s}$ , $t_{o} = 30\,s$ , $30\,s \le t \le 120\,s$ )

$v = 900-9.81\cdot (t-30)$ (3)

Now we created the graph speed-time, which can be seen below.

5 0

2 years ago

A group of students decides to set up an experiment in which they will measure the specific heat of a small amount of metal. The

lesya692 [45]

I think the answer is C

7 0

3 years ago