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3 years ago

14

PLEASE HELPP Look at the picture

2 answers:

denis23 [38]3 years ago

8 0

Answer: It’s c
explaining: i guessed

sveticcg [70]3 years ago

8 0

It’s either C. Or B. but it’s most probably B. Sorry if I’m incorrect.

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What can parents do if they find a mistake in the student records? A. They can’t do anything B. Make a correction themselve

Lelechka [254]

D. Ask the school to make the correction

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3 years ago

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In a football game, a receiver is standing still, having just caught a pass. Before he can move, a tackler, running at a velocit

ivolga24 [154]

Answer:

$m_{receiver}=115Kg*3.1/(1.6)-115Kg=107.8Kg$

Explanation:

The football players collide in a completely inelastic collision, in other words they have the same velocity after the collision, this velocity has a magnitude V=1.6m/s.

We need to use the conservation of momentum Law, the total momentum is the same before and after the collision, at the initial point the receiver does not have any speed

$m_{tackler}*v_{tackler}=(m_{tackler}+m_{receiver})V$ (1)

We solve in order to find the receiver mass:

$m_{receiver}={m_{tackler}*v_{tackler}/V}-m_{tackler}$

$m_{receiver}=115Kg*3.1/(1.6)-115Kg=107.8Kg$

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3 years ago

1. What is the potential energy of a 4-kilogram potted plant that is on a 1 meter-high plant

Yuri [45]

39.2 J

Explanation:

Step 1:

To find the potential energy the following formula is used.

Potential Energy = m × g × h

Where,

m = Mass

g = Acceleration due to gravity

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Step 2:

Here m = 4 kg, g = 9.8 m/s², h = 1 m

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4 years ago

Which of the following terms refer to the area immediately around the crime?

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3 years ago

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suter [353]

Answer:

the angular velocity of the carousel after the child has started running =

$\frac{2F}{mR} \delta t$

Explanation:

Given that

the mass of the child = m

The radius of the disc = R

moment of inertia I = $\frac{1}{2} mR^2$

change in time = $\delta \ t$

By using the torque around the inertia ; we have:

T = I×∝

where

R×F = I × ∝

R×F = $\frac{1}{2} mR^2$ ∝

F = $\frac{1}{2} mR$ ∝

∝ = $\frac{2F}{mR}$ ( expression for angular angular acceleration)

The first equation of motion of rotating wheel can be expressed as :

$\omega = \omega_0 + \alpha \delta t$

where ;

∝ = $\frac{2F}{mR}$

Then;

$\omega = 0+ \frac{2F}{mR} \delta t$

$\omega = \frac{2F}{mR} \delta t$

∴ the angular velocity of the carousel after the child has started running =

$\frac{2F}{mR} \delta t$

7 0

3 years ago