Fourth and fifth and what is come before latter e

A beam of white light passes through a uniform thickness of air. If the intensity of the scattered light in the middle of the gr

k0ka [10]

This question is incomplete, the complete question is;

A beam of white light passes through a uniform thickness of air. If the intensity of the scattered light in the middle of the green part of the visible spectrum (λ=520nm) is I, find the intensity (in terms of I) of scattered light

a) In the middle of the red part of the spectrum (λ= 665 nm)

b) In the middle of the violet part of the spectrum (λ = 420 nm)

Answer:

a) the intensity of scattered light ( in terms of $I$ ) In the middle of the red part of the spectrum is 0.3739 $I$

b) the intensity of scattered light ( in terms of $I$ ) In the middle of the violet part of the spectrum is 2.3497 $I$

Explanation:

Given the data in the question,

the visible spectrum (λ=520nm) = $I$

we know that; intensity of scattered light is proportional to 1 / λ⁴

$I$ ∝ ( 1 / λ⁴ )

so

a)

$I_R$ / $I$ = ( λ / λ $_R$ )⁴

As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ $_R$ is 665 nm

we substitute

$I_R$ / $I$ = ( 520 / 665 )⁴

$I_R$ / $I$ = ( 0.781954887 )⁴

$I_R$ / $I$ = 0.3739

$I_R$ = 0.3739 $I$ { in terms of $I$ }

Therefore, the intensity of scattered light ( in terms of $I$ ) In the middle of the red part of the spectrum is 0.3739 $I$

b)

$I_V$ / $I$ = ( λ / λ $_V$ )⁴

As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ $_R$ is 420 nm

we substitute

$I_V$ / $I$ = ( 520 / 420 )⁴

$I_V$ / $I$ = ( 1.238095 )⁴

$I_V$ / $I$ = 2.3497

$I_V$ = 2.3497 $I$ { in terms of $I$ }

Therefore, the intensity of scattered light ( in terms of $I$ ) In the middle of the violet part of the spectrum is 2.3497 $I$

5 0

3 years ago

Read 2 more answers

Chapter 38, Problem 001

Norma-Jean [14]

Answer:

a) $\lambda=2.95x10^{-6}m$

b) infrared region

Explanation:

Photon energy is the "energy carried by a single photon. This amount of energy is directly proportional to the photon's electromagnetic frequency and is inversely proportional to the wavelength. If we have higher the photon's frequency then we have higher its energy. Equivalently, with longer the photon's wavelength, we have lower energy".

Part a

Is provide that the smallest amount of energy that is needed to dissociate a molecule of a material on this case 0.42eV. We know that the energy of the photon is equal to:

$E=hf$

Where h is the Planck's Constant. By the other hand the know that $c=f\lambda$ and if we solve for f we have:

$f=\frac{c}{\lambda}$

If we replace the last equation into the E formula we got:

$E=h\frac{c}{\lambda}$

And if we solve for $\lambda$ we got:

$\lambda =\frac{hc}{E}$

Using the value of the constant $h=4.136x10^{-15} eVs$ we have this:

$\lambda=\frac{4.136x10^{15}eVs (3x10^8 \frac{m}{s})}{0.42eV}=2.95x10^{-6}m$

$\lambda=2.95x10^{-6}m$

Part b

If we see the figure attached, with the red arrow, the value for the wavelenght obtained from part a) is on the infrared region, since is in the order of $10^{-6}m$

4 0

3 years ago

Solve 305809 square root by division method

Rus_ich [418]

You use long division.

Find the largest number whose square is less than or equal to the number in the leftmost group (55 < 30 < 66). Take this number as the divisor and the quotient with the number in the leftmost group as the dividend (30). Divide and get the remainder (5 in this case).

Bring down the next pair 58. Add the divisor with the quotient and enter it with a blank on its right. Guess a largest possible digit to fill the blank which will also become the new digit in the quotient, such that when the new divisor is multiplied to the new quotient the product is less than or equal to the dividend. In this case 105 × 5 = 525, so we choose the new digit as 5. Get the remainder.

Bring down the next pair 09. Add the divisor with the quotient and enter it with a blank on its right. Guess a largest possible digit to fill the blank which will also become the new digit in the quotient, such that when the new divisor is multiplied to the new quotient the product is less than or equal to the dividend. In this case 1103 × 3 = 3309, so we choose the new digit as 3. Get the remainder.

Put the decimal point.

End of division (Remainder is 0 and next digit after decimal is 0).

√305809 = 553

8 0

4 years ago

The car has a constant deceleration of 4.20 m/s^2. If its initial velocity was 24.0 m/s, how long does it take to come to a stop

nalin [4]

Answer:

The time is 5.71 sec.

Explanation:

Given that,

Acceleration $a= -4.20 m/s^2$