Answer:
The launched cannonball
Explanation:
Consider,
The mass of the cannonball, m
The mass of the cannon, M = 1000 m
The velocity of the cannon, V
The velocity of the cannonball, v = 100 V
The K.E of the cannon, K.E = ½ MV²
The K.E of the cannonball, k.e = ½ mv²
Substituting the values in the K.E of the cannon
½ MV² = ½ x 1000 m x (v/100² )
= ½ mv²/ 10
Therefore, ½ mv² = 10 x ½ MV²
The K.E of the cannonball is 10 times the K.E of the cannon.
Hence, the cannonball has a grater K.E
