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3 years ago

11

an automobile engineer found that the impact of a truck colliding at 16 km/h with a concrete pillar caused the bumper to indent

only 6.4 cm. The truck stopped. Determine the acceleration.

1 answer:

Zolol [24]3 years ago

8 0

<span>To find the acceleration we are given two facts to begin. The impact at 16 km/h and the dent of 6.4 cm, or 0.064 meters. In solving the problem uniform acceleration is assumed, which would mean the avg speed during the impact was 8 km/hr by taking 16/2. We know distance = rate*time (d=r*t) . So t = d / r, so 0.64/8 = 0.008hr for t. Now we can solve for acceleration by taking a = 16 / 0.008 = 2000 km/hr.</span>

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A solenoid 1.39 m long and 3.20 cm in diameter carries a current of 17.1 A. The magnetic field inside the solenoid is 26.9 mT. F

Mariulka [41]

Explanation:

It is given that,

Length of the solenoid, l = 1.39 m

Diameter of the solenoid, d = 3.2 cm = 0.032 m

Radius of solenoid, r = 0.016 m

Magnetic field inside the solenoid, $B=26.9\ mT=26.9\times 10^{-3}\ T$

We need to find the length of the wire forming the solenoid. The magnetic field inside the solenoid is given by :

$B=\mu_o nI$

n is number of turns per unit length

$B=\dfrac{\mu_o NI}{l}$

$N=\dfrac{Bl}{\mu_o I}$

$N=\dfrac{26.9\times 10^{-3}\times 1.39}{4\pi \times 10^{-7}\times 17.1}$

N = 1740.04

The total length having N loop is,

$L=2\pi r\times N$

$L=2\pi \times 0.016\times \times 1740.04$

L = 174.92 m

So, the length of the wire forming the solenoid is 174.92 meters. Hence, this is the required solution.

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4 years ago

Suppose you place an object 8 cm in front of a converging lens and the image appears 16 cm on the other side of the lens. What i

Marianna [84]

Answer:

5.33 cm

Explanation:

The lens equation states that:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

In this problem,

p = 8 cm

q = 16 cm ( the sign is positive since the image is real, which means it is formed on the other side of the lens)

Substituting into the equation,

$\frac{1}{f}=\frac{1}{8 cm}+\frac{1}{16 cm}=\frac{3}{16 cm}$

$f=\frac{16}{3}cm=5.33 cm$

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3 years ago

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Troyanec [42]

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4 years ago

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How would something make more energy in order to travel farther and faster

Darya [45]

Answer:

hit it harder

Explanation:

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3 years ago

A 6.0-cm-diameter, 11-cm-long cylinder contains 100 mg of oxygen (O2) at a pressure less than 1 atm. The cap on one end of the c

g100num [7]

Explanation:

The given data is as follows.

Mass of oxygen present = 100 mg = $100 \times 10^{-3}$ g

So, moles of oxygen present are calculated as follows.

n = $\frac{100 \times 10^{-3}}{32}$

= $3.125 \times 10^{-3}$ moles

Diameter of cylinder = 6 cm = $6 \times 10^{-2}$ m

= 0.06 m

Now, we will calculate the cross sectional area (A) as follows.

A = $\pi \times \frac{(0.06)^{2}}{4}$

= $2.82 \times 10^{-3} m^{2}$

Length of tube = 11 cm = 0.11 m

Hence, volume (V) = $2.82 \times 10^{-3} \times 0.11$

= $3.11 \times 10^{-4} m^{3}$

Now, we assume that the inside pressure is P .

And, $P_{atm}$ = 100 kPa = 100000 Pa,

Pressure difference = 100000 - P

Hence, force required to open is as follows.

Force = Pressure difference × A

= $(100000 - P) \times 2.82 \times 10^{-3}$

We are given that force is 173 N.

Thus,

$(100000 - P) \times 2.82 \times 10^{-3}$ = 173

Solving we get,

P = $3.8650 \times 10^{4} Pa$

= 38.65 kPa

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So, we will put the values into the above formula as follows.

PV = nRT

$38.65 \times 3.11 \times 10^{-4} = 3.125 \times 10^{-3} \times 8.314 \times T$

T = 462.66 K

Thus, we can conclude that temperature of the gas is 462.66 K.

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3 years ago