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Art [367]
4 years ago
6

Two liters of a perfect gas are at 0>c and 1 atm. if the gas is nitrogen, n2, determine the number of molecules.

Chemistry
1 answer:
ZanzabumX [31]4 years ago
4 0

Solution;

The gas is at STP;

Where; T = 273 K , P = 1 atm

We know that 1 mole of a gas at STP occupies a volume of 22.4 liters .

V1/n1 = V2/n2

n2 = (V2/V1) n1

n2 = (2 l/22.4 l)(1 mole)

n2 = 0.0893 moles

But 1 mole of a compound has 6.022 × 10^23 molecules

Thus, number of molecules = 0.0893 moles × 6.022 ×10^23 molecules

= 5.378 × 10^22 molecules.

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Answer:

  1. In this way, ph is determined by hydrogen ion concentration . In the case of neutral solution [H+] =10-7 which we call a ph of 7. This means, for example, that a hydrogen-ion concentration of a solution with a ph of 4 is 10-4 mol/l, meaning it contains 0.0001 mole of hydrogen ion in a solution of 1 liter.

5 0
3 years ago
How many mg of metallic ions are in 1.0 mL of 0.10 M LINO3
Anton [14]

Answer:

0.6941 mg

Explanation:

First we <u>calculate how many LiNO₃ moles there are</u>, using the <em>given concentration and volume</em>:

  • 1.0 mL * 0.10 M = 0.10 mmol LiNO₃

As 1 mol of LiNO₃ contains 1 mol of Li,<em> in the problem solution there are 0.10 mmol of Li</em> (the only metallic ion present).

Now we<u> convert Li milimoles into miligrams</u>, using its <em>atomic mass</em>:

  • 0.10 mmol Li * 6.941 mg/mmol = 0.6941 mg

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3 years ago
What is the symbol for decimeter
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No need for an explanation

5 0
3 years ago
Read 2 more answers
How many moles in 4.93 x 10E23 atoms of silver?
leva [86]
<h3>Answer:</h3>

0.819 mol Ag

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

4.93 × 10²³ atoms Ag

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 4.93 \cdot 10^{23} \ atoms \ Ag(\frac{1 \ mol \ Ag}{6.022 \cdot 10^{23} \ atoms \ Ag})
  2. Divide:                              \displaystyle 0.818665 \ mol \ Ag

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.818665 mol Ag ≈ 0.819 mol Ag

8 0
3 years ago
If one were asked to choose between paper or plastic which would be chosen and which one would benefit the environment?
vekshin1
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