37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2
<span>4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms</span>
Answer:
HCl (aq) + NaOH (aq) --> H2O (L) + NaCl (aq)
Explanation:
HCl is a strong acid while NaOH is a strong alkali. Hence both should dissociate completely in water and 1 mol of HCl will fully neutralise 1 mol of NaOH.
I'm assuming that Part 2 on molarity is part of a data based question that requires you to calculate the number of moles of NaOH based on the data provided and the equation that you are required to balance. Hence, I can't help you with it as I do not have the values.
Hello!
The light from the sun hits one side of the moon and doesn’t hit from the other side. So that’s how we view it on earth
Hope this helps! Correct me if I’m wrong :)
-peachimin
the force between the electron and the proton.
a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
the radial acceleration of the electron.
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
the speed of the electron.
c) Now use a = v² / r
where a was found above
and r was given
<span> the period of the circular motion.</span>
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given
Answer:
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Explanation: