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Anarel [89]
2 years ago
8

What is the slope of the line with equation y=-5x

Mathematics
1 answer:
harina [27]2 years ago
3 0
An equation in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

In this case, our y-intercept is 0, so we're left with y = -5x.

-5 is in the place of m, which means -5 is our slope.


The slope of y = -5x is -5.
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Amanda needs to make a garden plot which has an area less than 18 sq. feet. The length should be 3 feet longer than the width. W
SCORPION-xisa [38]

Answer:

<em>Any width less than 3 feet</em>

Step-by-step explanation:

<u>Inequalities</u>

The garden plot will have an area of less than 18 square feet. If L is the length of the garden plot and W is the width, the area is calculated by:

A = L.W

The first condition can be written as follows:

LW < 18

The length should be 3 feet longer than the width, thus:

L = W + 3

Substituting in the inequality:

(W + 3)W < 18

Operating and rearranging:

W^2 + 3W - 18 < 0

Factoring:

(W-3)(W+6)<0

Since W must be positive, the only restriction comes from:

W - 3 < 0

Or, equivalently:

W < 3

Since:

L = W + 3

W = L - 3

This means:

L - 3 < 3

L < 6

The width should be less than 3 feet and therefore the length will be less than 6 feet.

If the measures are whole numbers, the possible dimensions of the garden plot are:

W = 1 ft, L = 4 ft

W = 2 ft, L = 5 ft

Another solution would be (for non-integer numbers):

W = 2.5 ft, L = 5.5 ft

There are infinitely many possible combinations for W and L as real numbers.

6 0
2 years ago
Anyone have the answer for this
sergiy2304 [10]

\huge\bold{Given:}

Length of the base = 16 km.

Length of the hypotenuse = 34 km. \huge\bold{To\:find:}

✎ The length of the missing leg ''a".

\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

The length of the missing leg "a" is\boxed{30\:km}.

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

Using Pythagoras theorem, we have

({perpendicular})^{2}  +  ({base})^{2}  =  ({hypotenuse})^{2}  \\ ⇢ {a}^{2}  +  ({16 \: km})^{2}  =  ({34 \: km})^{2}  \\ ⇢ {a}^{2}   + 256 \:  {km}^{2}  = 1156 \:  {km}^{2}  \\ ⇢ {a}^{2}  = 1156 \:  {km}^{2}  - 256 \:  {km}^{2}  \\ ⇢ {a}^{2}  = 900 \:  {km}^{2}  \\ ⇢a \:  =  \sqrt{900  \: {km}^{2} }  \\ ⇢a =  \sqrt{30 \times 30 \:  {km}^{2} }  \\ ⇢a = 30 \: km

\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}

\huge\bold{To\:verify :}

( {30 \: km})^{2}  +  ({16 \: km})^{2}  =(  {34 \: km})^{2}  \\ ⇝900 \:  {km}^{2}  + 256 \:  {km}^{2}  = 1156 \:  {km}^{2}  \\⇝1156 \:  {km}^{2}  = 1156 \:  {km}^{2}   \\ ⇝L.H.S.=R. H. S

Hence verified. ✔

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

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Answer:

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For the first picture :

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1.6003345 = 15 / x

x = 15 / 1.6003345

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y = sqrt(15^2 + 9.37^2)

y = sqrt(312.7969)

y = 17.7m

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Missing angle :

From ptthagoras :

Sin54° = opposite / hypotenus

0.8090169 = y/ 24

y = 0.8090169 * 24

y = 19.42

x = sqrt(24^2 - 19.42^2)

x = sqrt(198.8636)

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0.3583679 = 8 /y

y = 8 / 0.3583679

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x = sqrt(22.3^2 - 8^2)

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ivanzaharov [21]

Answer: 103/40, or 2 23/40 or, 2.575

Step-by-step explanation:

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Which row operation will trangularize this matrix?
Nadya [2.5K]

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2 years ago
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