The measure of Arc Q P is 96°. We also know that ∠QTP is central angle, then the measure of arc QP is 96°.
Step-by-step explanation:
<u>Step 1</u>
If QS is a circle diameter,
then m∠QTS=180°.
Let x be the measure of angle RTQ: ∠RTQ =x.
so, let ∠RTQ = x
<u />
<u>Step 2</u>
According to the question,
∠RTQ = ∠RTS - 12°
⇒ ∠RTS = x + 12°
∴ ∠QTS = ∠RTQ + ∠RTS
= x + x + 12° = 2x + 12° = 180°
⇒ 2x = 168°
⇒ x = 84°
⇒ ∠RTQ = 84°
<u></u>
<u>Step 3</u>
Now,
∵∠QTP and ∠RTS are vertical angles
∴ ∠QTP = 84° + 12° = 96°
As ∠QTP is the central angle, hence the measure of arc QP is 96°
<u></u>
<u>Step 4</u>
The Measure of arc QP = 96°
Answer:
11 units
Step-by-step explanation:
Since <em>∆ABC is isosceles, it means that at least two sides are congruent/equal in length</em>.
<em>Sides CA and AB are congruent</em>, since BC is the base. So, <em>CA = 4</em>.
That means the perimeter is <em>4 + 4 + 3 </em>= 11 un
11pi/6 is in 4th quadrant.
The reference angle is pi/6 because 11pi/6 is pi/6 radians away from 'x' axis.
In 4th quadrant, sin is negative and cos is positive, therefore tan is negative.
This means:
y + 6 = -3y + 26
+ 3y + 3y
4y + 6 = 26
- 6 - 6
4y = 20
4 4
y = 5
Answer:
<h2><u><em>
17/5</em></u></h2>
Step-by-step explanation:
whole number times the denominator plus the numerator equals the new numerator
3 x 5 = 15 + 2 = 17
