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Elan Coil [88]
2 years ago
10

Divide 60 in the ratio 3:9​

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
4 0

so the total number is 60, and we can just divide it by (3+9) and then distribute accordingly.

\stackrel{ratio~3:9}{60}\qquad \qquad 3\cdot \frac{60}{3+9}~~ :~~9\cdot \frac{60}{3+9}\implies 3\cdot \frac{60}{12}~~ :~~9\cdot \frac{60}{12} \\\\\\ 3(5)~~ : ~~9(5)\implies 15~~:~~45

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Answer:

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2. option D is correct i.e., \frac{a^3b^4}{ab^2}.

3. option B is correct i.e.,  \frac{n^{10}}{16m^{6}}.

Step-by-step explanation:

1. Since the given equation is:

\frac{-3a^{-2}b^3}{15a^{-7}b^{-1}}

As we know that a^{-x}=\frac{1}{a^x}

So, the given equation can be represented as:

\frac{-3a^{7}b^3b^1}{15a^{2}}


2. Given equation is:

\frac{a^3b^{-2}}{ab^{-4}}

As we know that a^{-x}=\frac{1}{a^x}

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\frac{a^3b^4}{ab^2}.


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(\frac{4mn}{m^{-2}n^6})^{-2}

by using the properties a^{-x}=\frac{1}{a^x},

and a^x\times a^y=a^{x+y}

(\frac{4mn}{m^{-2}n^6})^{-2}

= (\frac{4n^1n^{-6}}{m^{-2}m^{-1}})^{-2}

= (\frac{4n^{1+(-6)}}{m^{-2+(-1)}})^{-2}

= (\frac{4n^{-5}}{m^{-3}})^{-2}

= \frac{4^{-2}n^{-5\times (-2)}}{m^{-3\times (-2)}}

= \frac{n^{10}}{16m^{6}}.

which is option B.

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Step-by-step explanation:

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