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3 years ago

What is the net force acting on an object?

Physics

2 answers:

vodka [1.7K]3 years ago

4 0

Answer:

If two forces act on an object in the same direction, the net force is the sum of the two forces. In this case, the net force is always greater than either of the individual forces.

balu736 [363]3 years ago

3 0

I just finished this in science what i think is that both forces are equal and acting on each other causing them to cancel out ??

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Calculate the acceleration of an object slowing from 9.8 m/s to 6.4 m/s over the course of 17s

igor_vitrenko [27]

I have no idea sorry

8 0

3 years ago

A suspension bridge is 60.0 m above the level base of a gorge. A stone is thrown or dropped from the bridge. Ignore air resistan

Alexxx [7]

Answer:

a) $t_{1}=3.49s$

b) $t_{2}=2.00s$

c)Xmax=80.71m

Explanation:

a)Kinematics equation for the Stone, dropped:

$v(t)=v_{o}-g*t$

$y(t)=y_{o}+v_{o}t-1/2*g*t^{2}$

$y_{o}=h=60m$ initial position is bridge height

$v_{o}=0m/s$ the stone is dropped

The ball reaches the ground, y=0, at t=t1:

$0=h-1/2*g*t_{1}^{2}$

$t_{1}=\sqrt{2h/g}=\sqrt{2*60/9.83}=3.49s$

b)Kinematics equation for the Stone, with a initial speed of 20m/s:

$v(t)=v_{o}-g*t$

$y(t)=y_{o}+v_{o}t-1/2*g*t^{2}$

$y_{o}=h=60m$ initial position is bridge height

$v_{o}=-20m/s$ the stone is thrown straight down

The ball reaches the ground, y=0, at t=t1:

$0=h+v_{o}t_{2}-1/2*g*t_{2}^{2}$

$0=60-20t_{2}-1/2*9.83*t_{2}^{2}$

t2=-6.01 this solution does not have physical sense

t2=2.00

c)Kinematics equation for the Stone, with a initial speed of 20m/s with an angle of 30° above the horizontal:

$v(t)=v_{o}-g*t$

$y(t)=y_{o}+v_{o}t-1/2*g*t^{2}$

$y_{o}=h=60m$ initial position is bridge height

$v_{o}=20sin(30)=10m/s$ the stone is thrown with an angle of 30° above the horizontal

The ball reaches the ground, y=0, at t=t3:

$0=h+v_{o}t_{3}-1/2*g*t_{3}^{2}$

$0=60+10t_{3}-1/2*9.83*t_{3}^{2}$

t3=-2.62 this solution does not have physical sense

t3=4.66

the movement in x:

v=constant=20cos(30)m/s

x(t)=v*t

Xmax=v*t3=20cos(30)*4.66=80.71m

3 0

3 years ago

An aluminum calorimeter with a mass of 100 g contains 250 g of water. The calorimeter and water are in thermal equilibrium at 10

Nadya [2.5K]

Answer:

1822.14 J/kg C

Explanation:

Mass of aluminum = 0.100 kg

Mass of Water = 0.250 kg

Mass of copper = 0.300 kg

Mass of unknown object = 0.70 kg

Initial temperature of Aluminum = 10 C

Initial temperature of water = 10 C

Initial temperature of copper = 30 C

Initial temperature of = 100 C

Final temperature of all substances = 20 C

Change in temperature of each of them Aluminum, water , copper and unknown material respectively = 10 C , 10 C , -10 C, -80 C respectively

Specific heat of each of them Aluminum, water , copper and unknown material respectively = 900,4186,387 and c respectively.

Heat gained by aluminum and water = (0.1)(900)(10) + (0.250)(4186)(10) = 11365 j

heat lost by copper and unknown material =(0.3)(387)(-10) = -1161

heat lost by unknown material = (0.070)(c)(-80) = -5.6 c

Now solve for c using the calorimetry principle.

Heat lost + Heat gained = 0

⇒ -5.6 c = -11365 - (-1161) = -10204 j

Specific heat of unknown material = - 10204 / -5.6

= 1822.14 j/kg C

b) Material having a specific heat of 1800 j /kg C is

Polyurethane elastomer.

4 0

3 years ago

A wire is stretched right to its breaking point by a 5000 N force. A longer wire made of the same material has the same diameter

leva [86]

Answer:

Equal to 5000N

Explanation:

The stress on the material is defined by force per unit of cross-sectional area. So it depends on the force and the diameter of the wire, which is the same for both wires. The material that defines the breaking point, is also the same. Therefore, both wires have their breaking point the same at 5000N. The wire length plays no role in here.

4 0

3 years ago

Which of the following statements correctly describes the position of the intake and exhaust valves during most of the power sta

I am Lyosha [343]

Both valves are closed during the power stroke.

While the fuel is burning in the cylinder, you want
all the force of the expanding gases to push the
piston down ... you don't want any of the gases
or their pressure escaping.

If either of the valves was open, even just a crack,
then part of the gases would go blooey out the valve,
and some pressure would be lost that's supposed to be
pushing the piston.

5 0

3 years ago

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