The tension in the string holding the tassel and the vertical will the tension in the string
<h3>What is the tension in the string holding the tassel. ?</h3>
Generally, the equation for Tension is mathematically given as

Therefore

T = 0.1953 N
b).
Where


a = 1.13 m/s^2
In conclusion
T* sinФ = ma
2msinФ = ma
2sinФ = a


Ф = 34.4 °
In conclusion, The tension in the string holding the tassel and the vertical will the tension in the string
T = 0.1953 N
Ф = 34.4 °
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Answer:
The equivalent capacitance will be
Explanation:
We have given two capacitance 
They are connected in parallel
So equivalent capacitance 
This equivalent capacitance is now connected in series with 
In series combination of capacitors the equivalent capacitance is given by 

So the equivalent capacitance will be
Answer:
E=1100V/m
Explanation:
Given required <u>solution</u>
V=6.6v E=? V=Ed ; V is the potential difference between
d=D/2=1.2cm/2=0.6cm=0.006m the halfway
E is the electric field between the two
plates.
d is the distance between the halfway.
So we can use the above formula to calculate the electric field.
V=Ed from this E=V/d substitute the values from the given equation.
E=6.6v/0.006m
E= 1100 v/m