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3 years ago

Does visible light make up a relatively large part or a relatively small part of the electromagnetic spectrum?

Physics

1 answer:

Yakvenalex [24]3 years ago

8 0

Answer:

Relatively small part of the electromagnetic spectrum

Explanation:

Let us take a look at the electromagnetic spectrum

Radio waves

Wavelength = $10^3\ m$

Microwaves

Wavelength = $10^{-2}\ m$

Infrared waves

Wavelength = $10^{-5}\ m$

Visible waves

Wavelength = $0.5\times 10^{-6}\ m$

Radio waves

Wavelength = $10^3\ m$

Ultraviolet waves

Wavelength = $10^{-8}\ m$

X ray waves

Wavelength = $10^{-10}\ m$

Gamma ray waves

Wavelength = $10^{-12}\ m$

So, it can be seen that the visible light makes up a relatively small part of the electromagnetic spectrum.

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which of the following is not a projectile? a.a satellite b.a throw ball c.a ball on the ground d.a soaring arrow

Delvig [45]

C a ball on the ground

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3 years ago

Read 2 more answers

A 0.10- kg ball is thrown straight up into the air with

mezya [45]

Answer:(a)0,(b)1.061 kg-m/s

Explanation:

Given

mass of ball is 0.10 kg

Initial speed is 15 m/s

Maximum height reached by ball is h

$v^2-u^2=2as$

final velocity =0

$-\left ( 15\right )^2=-2\times 9.81\times s$

$s=\frac{15^2}{2\times 9.81}=11.467 m$

thus momentum of ball at maximum height is 0 as velocity is zero

For halfway to maximum height

$v^2-u^2=2as_0$

where $s_0=\frac{11.467}{2}$

$s_0=5.73 m$

$v^2=15^2-2\times 9.81\times 5.73$

v=10.61 m/s

Thus its momentum is

$mv=0.10\times 10.61=1.061 kg-m/s$

3 0

3 years ago

What total energy (in J) is stored in the capacitors in the figure below (C1 = 0.900 µF, C2 = 16.0 µF) if 1.80 10-4 J is stored

Musya8 [376]

The total energy stored in the capacitors is determined as 2.41 x 10⁻⁴ J.

<h3>What is the potential difference of the circuit?</h3>

The potential difference of the circuit is calculated as follows;

U = ¹/₂CV²

where;

C is capacitance of the capacitor
V is the potential difference

For a parallel circuit the voltage in the circuit is always the same.

The energy stored in 2.5 μf capacitor is known, hence the potential difference of the circuit is calculated as follows;

U = ¹/₂CV²

2U = CV²

V = √2U/C

V = √(2 x 1.8 x 10⁻⁴ / 2.5 x 10⁻⁶)

V = 12 V

The equivalent capacitance of C1 and C2 is calculated as follows;

1/C = 1/C₁ + 1/C₂

1/C = (1)/(0.9 x 10⁻⁶) + (1)/(16 x 10⁻⁶)

1/C = 1,173,611.11

C = 1/1,173,611.11

C = 8.52 x 10⁻⁷ C

The total capacitance of the circuit is calculated as follows;

Ct = 8.52 x 10⁻⁷ C + 2.5 x 10⁻⁶ C

Ct = 3.35 x 10⁻⁶ C

The total energy of the circuit is calculated as follows;

U = ¹/₂CtV²

U = ¹/₂(3.35 x 10⁻⁶ )(12)²

U = 2.41 x 10⁻⁴ J

Learn more about energy stored in a capacitor here: brainly.com/question/14811408

#SPJ1

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1 year ago

After impairing memory, focus, and reasoning, alcohol next causes a deterioration in __________.

Lera25 [3.4K]

Hi there!

The next thing that alcohol affects is <span>B. basic muscle control. The reason for this is that alcohol is what is called a "depressant" which means it relaxes the body and mind during the euphoria.

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2 years ago

Please help, I really need this. Thanks

mariarad [96]

Answer

Delta Q = change in thermal energy = c M * change in temperature

change in temperature = Q / (c * M)

change in temperature = -12 J / (390 J / Kg*deg * .012 kg

change in temp = -12 / (390 * .012) = - 2.56 deg C

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2 years ago