All categories

3 years ago

A total of 2.0x 1013 electrons pass a given point in a wire in 15s. what is the current in the wire

1 answer:

4 0

The current in a wire is defined as the amount of charge that passes a given point of the wire in a given time:
$I= \frac{Q}{\Delta t}$
where Q is the charge and $\Delta t$ is the time interval.

Since one electron has a charge of $q=1.6 \cdot 10^{-19}C$ , the total charge of $2.0 \cdot 10^{13}$ electrons is
$Q=qN=(1.6 \cdot 10^{-19} C)(2.0 \cdot 10^{13} )=3.2 \cdot 10^{-6} C$

And since the time interval is $\Delta t=15 s$ , the current in the wire is
$I= \frac{Q}{\Delta t}= \frac{3.2 \cdot 10^{-6} C}{15 s}=2.1 \cdot 10^{-7}A$

You might be interested in

Forces can act on an object in the same direction or in opposite. how does each situation affect the motion of the object?

Anon25 [30]

Hi pupil here's your answer ::

➡➡➡➡➡➡➡➡➡➡➡➡➡

Action and Reaction do not act on the same body !! If they acted on the same body, the resultant force will be zero and their could be never accelerated motion.

If both the forces acted on the same body, then if they are equal to opposite direction the object will remain stationary. If on of the forces is greater than other the object will move in the direction of greater force.

If both acted in the same direction there would be an accelrated motion.

⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅

Hope this helps . . . . .

5 0

3 years ago

A cyclist rides 16.0 km east, then 8.0 km west, then 8.0 km east, then 32.0 km west, and finally 11.2 km east.

Anna71 [15]

Answer:

Time, t = 12 minutes

Explanation:

It is given that,

A cyclist rides 16.0 km east, then 8.0 km west, then 8.0 km east, then 32.0 km west, and finally 11.2 km east. Let west direction is negative and east direction is positive. The displacement of the cyclist is :

$d=16-8+8-32+11.2=-4.8\ km$

d = 4800 m

Let us assumed that the average speed of the cyclist is, v = 24 km/h = 6.66667 m/s

Let t is the time taken by the cyclist to complete the trip. The velocity of an object is given by :

$v=\dfrac{d}{t}$

$t=\dfrac{d}{v}$

$t=\dfrac{4800\ m}{6.66667\ m/s}$

t = 719.99 seconds

t = 720 seconds

t = 12 minutes

So, the time taken by the cyclist to complete the trip is 12 minutes. Yes, the time taken by the cyclist to complete the trip is reasonable. Hence, this is the required solution.

7 0

4 years ago

Help would be greatly appreciated:) thank you! a pendulum clock is brought to mars. How does the bob move on Mars as compared to

Alborosie

It runs slower <span>as gravity is lower so acceleration due to gravity is smaller</span>

8 0

3 years ago

A stretched string has a mass per unit length of 5.40 g/cm and a tension of 17.5 N. A sinusoidal wave on this string has an ampl

kondaur [170]

Answer:

Part a)

$y_m = 0.157 mm$

part b)

$k = 101.8 rad/m$

Part c)

$\omega = 579.3 rad/s$

Part d)

here since wave is moving in negative direction so the sign of $\omega$ must be positive

Explanation:

As we know that the speed of wave in string is given by

$v = \sqrt{\frac{T}{m/L}}$

so we have

$T = 17.5 N$

$m/L = 5.4 g/cm = 0.54 kg/m$

now we have

$v = \sqrt{\frac{17.5}{0.54}}$

$v = 5.69 m/s$

now we have

Part a)

$y_m$ = amplitude of wave

$y_m = 0.157 mm$

part b)

$k = \frac{\omega}{v}$

here we know that

$\omega = 2\pi f$

$\omega = 2\pi(92.2) = 579.3 rad/s$

so we have

$k = \frac{579.3}{5.69}$

$k = 101.8 rad/m$

Part c)

$\omega = 579.3 rad/s$

Part d)

here since wave is moving in negative direction so the sign of $\omega$ must be positive

4 0

4 years ago

what is the magnitude of the electric force between charges of 0.25 C and 0.11 C at a separation of 0.88 m? if the separation be

leonid [27]

$F = k \cdot \frac{q_1 q_2}{d} = 9 \cdot 10^{9} \cdot \frac{0.25 \cdot 0.11}{0.88} = 144 \cdot 5^{9} \ N.$

If the separation between the charges is increased then the magnitude of the force will increase in fact how the distance is being used in that formula.

6 0

3 years ago