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Gnom [1K]
3 years ago
13

Write an equation, then determine the number described in the following statement: Eight less than 3 times a number is twice the

sum of x and 4.
Mathematics
1 answer:
spayn [35]3 years ago
6 0
So eight (8) less than (3) times a number ( 8 - 3x) is (=) twice the sum of x (2x) and (4) so the answer would be 8 - 3x = 2x + 4
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Find f(-3) if f(x) = x 2.<br> A) 6<br> B-9<br> C)9<br> D-6
Firlakuza [10]

Answer: f(-3)=(-3)^2

f(-3)=9

the answer is C

Step-by-step explanation:

8 0
3 years ago
A standard basketball court is 50 feet by 94 feet what is the total surface area in square feet?
elena-14-01-66 [18.8K]
The answer is 4,700 square feet
4 0
3 years ago
Solve 91 - 2 + 7k| +1 = 46
mylen [45]

Answer:

k = -6.29

Step-by-step explanation:

91 - 2 + 7k + 1 = 46

add all like terms

90 + 7k =46

subtract

90 + 7k = 46

-90          -90

------------------------

7k = -44

divide

\frac{7k}{7} = \frac{-44}{7} (these arent fractions thats just how i divide things :))

= -6.28571428571

round to nearest hundredth

k= -6.29

goes up to 9 because 5 makes 8 go up one when rounding

sorry for asking so many questions. hope this helps

7 0
3 years ago
Find the Volume for number 1 , 2 and 3
Usimov [2.4K]
For the first one I got : 
V = 165/8
 V = B*h
(B)11/2 * (h)15/4 
= 165/8


Pls correct me if im wrong!! :)
3 0
3 years ago
The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp
Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

The standard deviation of the sample is the same as the standard error of the mean. So

SE_{M} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 0.35, n = 20

So

SE_{M} = \frac{\sigma}{\sqrt{n}}

SE_{M} = \frac{0.35}{\sqrt{20}}

SE_{M} = 0.0783

The standard error of the mean is 0.0783.

7 0
3 years ago
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