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marusya05 [52]
2 years ago
11

Solve pls brainliest

Mathematics
1 answer:
Lyrx [107]2 years ago
8 0

Answer:

a. 9m/s × 27s = 243m

b. -6°C/3hrs = -2°C/hr

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Plss help me with my questions plsss <br>plss help me plsss​
yarga [219]

Answer:

11. 3.8 12. .009 13. 5.1 14. .678 15. 37.0800

6 0
3 years ago
Read 2 more answers
A waiter at a restaurant automatically earns a certain percent tip on each bill. On a $45 dinner, the waiter makes $9 in tips. W
Oduvanchick [21]

Answer:

$45 dinner = $9

$1 dinner = 45/9= 5

$60 dinner = 60/5=12

Hence he got $12 for a $60 dinner

3 0
3 years ago
I thought of a number, I added 1 3 4 to it, then I multiplied the result by 2 2 11 and I got 8. What was my number?
Valentin [98]

Given:

In a number, adding 1\dfrac{3}{4}, then multiplying the result by 2\dfrac{2}{11} we get 8.

To find:

The unknown number.

Solution:

Let the unknown number be x.

According to the question,

(x+1\dfrac{3}{4})\times 2\dfrac{2}{11}=8

(x+\dfrac{1\times 4+3}{4})\times \dfrac{2\times 11+2}{11}=8

(x+\dfrac{4+3}{4})\times \dfrac{22+2}{11}=8

(x+\dfrac{7}{4})\times \dfrac{24}{11}=8

Multiply both sides by \dfrac{11}{24}.

x+\dfrac{7}{4}=8\times \dfrac{11}{24}

x+\dfrac{7}{4}=\dfrac{11}{3}

Subtract \dfrac{7}{4} from both sides.

x=\dfrac{11}{3}-\dfrac{7}{4}

x=\dfrac{44-21}{12}

x=\dfrac{23}{12}

x=1\dfrac{11}{12}

Therefore, the required number is 1\dfrac{11}{12}.

3 0
3 years ago
PLEASE HELP!!!!
Lunna [17]

NOTES:

Given a quadratic function in standard format (y = ax² + bx + c), the direction of the parabola is as follows:

  • if "a" is positive, then opens UP
  • if "a" is negative, then opens DOWN

Given a quadratic function in standard format (y = ax² + bx + c), the vertex can be found as follows:

  • the Axis Of Symmetry (x-value) is: x = \frac{-b}{2a}  
  • y-value is found by plugging in the AOS for "x" in the equation

****************************************************************************************

1) y = x² + 11x + 24

  • a = +1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-11}{2(1)}  = -\frac{11}{2}
  • y = (-\frac{11}{2})^{2} + 11(-\frac{11}{2} ) + 24 = -\frac{25}{4}
  • vertex (-\frac{11}{2}, -\frac{25}{4}) is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-3, 0) and (-8, 0), and y-intercept (0, 24)

******************************************************************************************

2) y = -x² - 6x - 8

  • a = -1 so the parabola opens DOWN
  • x = \frac{-b}{2a} = \frac{-(-6)}{2(-1)}  = \frac{6}{-2} = -3
  • y = -(-3)² - 6(-3) - 8 = -9 + 18 - 8 = 1
  • vertex (-3, 1) is in Quadrant 2 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-4, 0), and y-intercept (0, -8)

******************************************************************************************

3) y = x² - 2x + 3

  • a = 1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-(-2)}{2(1)}  = \frac{2}{2} = 1
  • y = (1)² - 2(1) + 3 = 1 - 2 + 3 = 2
  • vertex (1, 2) is in Quadrant 1 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 3), and its mirror image (2, 3). <em>There are no x-intercepts</em>

******************************************************************************************

4) y = x² + 4x + 4

  • a = 1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-4}{2(1)}  = -2
  • y = (-2)² + 4(-2) + 4 = 4 - 8 + 4 = 0
  • vertex (-2, 0) is in Quadrant 2 and is on the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 4), and its mirror image (-4, 4). <em>The x-intercept is the vertex.</em>

Compared to the other four graphs, this is most likely the equation for the rain gauge!

******************************************************************************************

5) y = 3x² + 21x + 30

  • a = +3 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-21}{2(3)}  = -\frac{7}{2}
  • y = 3(-\frac{7}{2})^{2} + 21(-\frac{7}{2} ) + 30 = -\frac{27}{4}
  • vertex (-\frac{7}{2}, -\frac{27}{4}) is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-5, 0), and y-intercept (0, 30)

*******************************************************************************************

4 0
3 years ago
Read 2 more answers
What is 7! Like seven times all the numbers below it
aleksandr82 [10.1K]
Explain yourself more and I’ll help
3 0
3 years ago
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