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marusya05 [52]
2 years ago
11

Solve pls brainliest

Mathematics
1 answer:
Lyrx [107]2 years ago
8 0

Answer:

a. 9m/s × 27s = 243m

b. -6°C/3hrs = -2°C/hr

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Drag each label to the correct location on the graph. Not all labels will be used.
mamaluj [8]

Answer:

Not all labels will be used. ... They charge a certain rate for the rental of a sailboat and an additional ... according to the length of time for which the tourists rent the boat.

4 0
2 years ago
The probability of flu symptoms for a person not receiving any treatment is 0.038. In a clinical trial of a common drug used to
alexgriva [62]

Answer:

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 1164, p = 0.038

So

\mu = E(X) = np = 1164*0.038 = 44.232

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = 6.5231

Estimate the probability that at least 47 people experience flu symptoms.

Using continuity correction, this is P(X \geq 47 - 0.5) = P(X \geq 46.5), which is 1 subtracted by the pvalue of Z when X = 46.5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{46.5 - 44.232}{6.5231}

Z = 0.35

Z = 0.35 has a 0.6368

1 - 0.6368 = 0.3632

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

6 0
3 years ago
What is 2700 divided 90​
crimeas [40]

Answer:

30

Step-by-step explanation:

2700/90 = 30

27/9 = 3

100/10 = 10

3*10 = 30

8 0
3 years ago
Hii please help i’ll give brainliest if you give a correct answer please please hurry it’s timed
Alexxandr [17]
Answer:

The first book ur
3 0
3 years ago
A total of 123 fifth-grade students are going to ford Verde state historic park each bus holds 38 students all of the buses are
FromTheMoon [43]

Hi Lala4eva54,

Your Question:

A total of 123 fifth-grade students are going to ford Verde state historic park each bus holds 38 students all of the buses are full Except one how many students will be in the bus that is not feel.

Solution:

123 / 38 = 3.236.....

38 x 3 = 114

123 - 114 = 9

Answer:

There will be 9 students in the bus thats not full.

4 0
3 years ago
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