Answer:
Step-by-step explanation:
![{\huge{\boxed{\sf{Question}}](https://tex.z-dn.net/?f=%7B%5Chuge%7B%5Cboxed%7B%5Csf%7BQuestion%7D%7D)
![-1.2= y\div2.4 -1.7](https://tex.z-dn.net/?f=-1.2%3D%20y%5Cdiv2.4%20-1.7)
Solve for y
![{\huge{\boxed{\sf{Answer\:with\:explanation }}}](https://tex.z-dn.net/?f=%7B%5Chuge%7B%5Cboxed%7B%5Csf%7BAnswer%5C%3Awith%5C%3Aexplanation%09%7D%7D%7D)
let's put our equation first
![-1.2= y\div2.4 -1.7](https://tex.z-dn.net/?f=-1.2%3D%20y%5Cdiv2.4%20-1.7)
Flip the equation
![y\div2.4-1.7=-1.2](https://tex.z-dn.net/?f=y%5Cdiv2.4-1.7%3D-1.2)
Now follow the rule of ![BOMDAS/PEMDAS](https://tex.z-dn.net/?f=BOMDAS%2FPEMDAS)
![{\huge{\boxed{\sf{BOMDAS }}}](https://tex.z-dn.net/?f=%7B%5Chuge%7B%5Cboxed%7B%5Csf%7BBOMDAS%09%7D%7D%7D)
![{\huge{\boxed{\sf{PEMDAS}}}](https://tex.z-dn.net/?f=%7B%5Chuge%7B%5Cboxed%7B%5Csf%7BPEMDAS%7D%7D%7D)
_________________________
![{\huge{\boxed{\sf{Solve\:the\:equation}}}](https://tex.z-dn.net/?f=%7B%5Chuge%7B%5Cboxed%7B%5Csf%7BSolve%5C%3Athe%5C%3Aequation%7D%7D%7D)
_________________________
![y\div2.4-1.7=-1.2](https://tex.z-dn.net/?f=y%5Cdiv2.4-1.7%3D-1.2)
![{\underline{simplify}}](https://tex.z-dn.net/?f=%7B%5Cunderline%7Bsimplify%7D%7D)
![0.416667y-1.7=-1.2](https://tex.z-dn.net/?f=0.416667y-1.7%3D-1.2)
add
to both sides
![0.416667y=0.5](https://tex.z-dn.net/?f=0.416667y%3D0.5)
Divide both sides by ![0.416667](https://tex.z-dn.net/?f=0.416667)
![y=1.2](https://tex.z-dn.net/?f=y%3D1.2)
![{\huge{\boxed{\sf{Answer}}}](https://tex.z-dn.net/?f=%7B%5Chuge%7B%5Cboxed%7B%5Csf%7BAnswer%7D%7D%7D)
would equal ![1.2](https://tex.z-dn.net/?f=1.2)
Answer:
A) 0 ≤ x ≥ 5
B) Number line is attached
C) Interval notation is; (0,5)
Step-by-step explanation:
We are told that the number is greater than zero and less than or equal to 5. If the number is x, then we can write the inequality as;
i) 0 ≤ x ≥ 5
ii) The solution graphed on a number line is attached.
iii) Since 0 ≤ x or x ≥ 5, then the interval notation is; (0,5)
Answer:
26km
Step-by-step explanation:
d=speed × time
d=60×2.33
d= 140km
y= mx+b
(16, -7) = (x,y)
2(16) - 3y = 12
32 - 3y = 12
32 - 12 = 3y
20/3 = y
6.6 = y
2x-3(-7) = 12
2x+21 = 12
2x = 12 - 21
x = -9/2
Insert the values into y = mx + b
solve for m and then solve for b