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Verdich [7]
3 years ago
15

12%___=2b---Pls Help Me . . .

Mathematics
1 answer:
vampirchik [111]3 years ago
6 0

Your answer is 0.06

The way is Isolate the variable by dividing each side by factors that don't contain the variable.

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The Late Show with David Leterman is seen by a relatively large percentage of household members who record the show for viewing
Zanzabum

Answer:

a) Null hypothesis:\mu \leq 40000  

Alternative hypothesis:\mu > 40000  

b) t=\frac{41182-40000}{\frac{19990}{\sqrt{1700}}}=2.438    

c) The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since the sample size is large enough we cna use the z distribution as an approximation for the statsitic on this case.

Since is a one right tailed test the p value would be:  

p_v =P(t_{(1699)}>2.438)=0.0074  

d) If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis at 1% of signficance.  So we can conclude that the true mean is higher than 40000 at the significance level assumed.

Step-by-step explanation:

Data given and notation  

\bar X=41182 represent the sample mean

s=19990 represent the sample standard deviation

n=1700 sample size  

\mu_o =40000 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is greater than 40000, the system of hypothesis would be:  

Null hypothesis:\mu \leq 40000  

Alternative hypothesis:\mu > 40000  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{41182-40000}{\frac{19990}{\sqrt{1700}}}=2.438    

Part c: P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since the sample size is large enough we cna use the z distribution as an approximation for the statsitic on this case.

Since is a one right tailed test the p value would be:  

p_v =P(t_{(1699)}>2.438)=0.0074  

Part d: Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis at 1% of signficance.  So we can conclude that the true mean is higher than 40000 at the significance level assumed.

3 0
3 years ago
Write a decimal between 0.5 and 0.75 then write it as a fraction in simplest form
IgorLugansk [536]
Hello,

An example of a decimal between 0.5 and 0.75 is 0.6, written as 3/5 as a fraction in its simplest form.

Hope this helps!

3 0
3 years ago
Read 2 more answers
Calculate the length of side AC:
lisabon 2012 [21]

Answer:

146⁰ + x = 180

x = 34⁰ is AC ..a..a.

3 0
3 years ago
Wooden blocks are stacked to form a cube 3 blocks wide,3 blocks long, and 3 blocks high.How many blocks are used?
liraira [26]
27; The first stack is 3 x 3 (= 9). You then multiply 9 by 3 (for each of the 3 stacks). Basically, 3 x 3 x 3.
6 0
3 years ago
Read 2 more answers
Last Tuesday was silly hat day at Toby's school. 74 students wore a silly hat and 666 students did not. What percentage of the s
valina [46]

Answer:

10%

Step-by-step explanation:

The total population of students will be equal to the sum of both those who wore the silly hat and those who didn't hence

Total students= 74+666=740

Number of students who wore silly hat is given as 74 hence when expressed as a percentage of the total students' population we get that

percentage of the students wore a silly hat=\frac {74\times 100}{740}=10\%

Therefore, 10% of students wore a silly hat last Tuesday

4 0
3 years ago
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