Answer:
6x²y²
Step-by-step explanation:
6: 1 2 3 6
18: 1 2 3 6 9 18
36: 1 2 3 4 6 9 12 18 36
the common factor for 6 18 and 36 are
1 2 3 6
x² = x × x
y³ = y × y × y
x³ = x × x × x
y³ = y × y × y
x³ = x × x × x
y² = y × y
the common factor are for x and y are
x² y²
Multiply the GCF of the numerical part 6 and the GCF of the variable part x² y² to get 6x² y²
16 m³
Step-by-step explanation:
Step 1:
Here we are going to find the volume of square pyramid.
Volume of square pyramid =
×
× 
Here base = 4 m
Height = 3 m
Step 2:
Volume = (1/3) × (4 × 4) × 3
= 16 m³
Answer:
324
Step-by-step explanation:
Given:

Find:

First, find f(x):

Now,

2w+2(10)=30
multioly the 2 and 10
2w+20=30
subtract 20
2w=10
divide by 2
w=5
plz rate as brainliest answer