Step 1: 1
(((x3) - (2•5x2)) + 29x) - 30 = 0
Step 2 2.1 x3-10x2+29x-30 is not a perfect cube
Step 3 Factoring: x3-10x2+29x-30
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 29x-30
Group 2: -10x2+x3
Pull out from each group separately :
Group 1: (29x-30) • (1)
Group 2: (x-10) • (x2)
Answer:
35.29
Step-by-step explanation:
Answer:
A. (f+g)(x) means add the two functions, f and g
since f is 2x-2 and g is 6x, you'll just add them together
(f+g)(x)=2x-2+6x = 8x+2
B. (f-g)(x) means subtract the two functions, f and g
since f is 2x-2 and g is 6x, you'll just subtract
(f-g)(x)=2x-2-6x = -4x+2
C. (g-f)(x) I think you're getting the hang of it!
=6x-(2x-2) just be sure to put the second function in parentheses because you're subtracting the whole thing
=6x-2x+2 = 4x+2
D. (g+f)(x) try this on your own and check here
6x+(2x-2) = 6x+2x-2 = 8x-2
Step-by-step explanation:
to add or subtract functions, don't let the function notation throw you off. Pretend each one is just a number and you just add or subtract the whole thing. You got it! Next they will give you something like find (f+g)(5). All that means is add the two functions like in part a, and then in the final answer, plug in 5 instead of x. For example (f+g)(5) = 8x+2 = 8(5) +2 = 42
:)
Answer:
Step-by-step explanation: A
