At stp what is the volume of 5.35 moles of methane ch4

Solid iron (III) oxide reacts with hydrogen gas to form iron and water. How many grams of iron are produced when 440.23 grams of

Nookie1986 [14]

When 440.23 grams of iron(III) oxide are reacted with hydrogen gas, the amount of iron produced will be 307.66 grams

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

$Fe_2O_3 + 3H_2 --- > 2Fe + 3H_2O$

The mole ratio of iron(III) oxide to produced iron is 1:2.

Mole of 440.23 iron(III) oxide = 440.23/159.69 = 2.76 moles

Equivalent mole of produced iron = 2.76 x 2 = 5.52 moles

Mass of 5.52 moles of iron = 5.52 x 55.8 = 307.66 grams

More on stoichiometric calculations can be found here; brainly.com/question/27287858

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4 0

1 year ago

the atomic number of four elements p,q,r,s are 6,8,10 and 12 respectively. the two elements which can bond ionically are:

denis-greek [22]

Answer:

The atomic numbers of four elements A, B, C, and D are 6,8,10, and 12 respectively. The two elements which can react to form ionic bonds (or ionic compounds) are B (8= 2,6) and D (12 =2,8,2). So D donates its two electrons to B to fulfill their octet.

Explanation:

6 0

2 years ago

Based on the information given below, about how many trips around the Milky Way has the Sun made since the emergence of life on

miss Akunina [59]

It has oribited the milky way more then 20 times

3 0

3 years ago

When active metals such as magnesium are immersed in acid solution, hydrogen gas is evolved. Calculate the volume of H2(g) at 30

V125BC [204]

Answer:

The volume of H₂ (g) obtained is 22.4L

Explanation:

First of all, think the reaction:

2HCl (aq) + Zn (s) → ZnCl₂ (aq) + H₂ (g)

You have to add a 2, in the HCl to get ballanced.

Now we should know how many moles of each reactant, do we have.

Volume . Molarity = moles

Notice that volume is in mL, so I must convert to L.

275 mL = 0.275L

0.275L . 0.725mol/L = 0.2 moles of HCl

Molar mass of Zn: 65.41 g/m

50 g / 65.41 g/m = 0.764 moles

Ratio between reactants is 2:1, so I need the double of moles of HCl to react, and a half moles of Zn to react.

My limiting reactant is the HCl, for 0.764 moles of Zinc, I need 1.528 (0.764 .2) of HCl, and I only have 0.2 moles.

Ratio between HCl and H₂ is 1:1, so 0.2 HCl make 0.2 moles of gas

Now apply the Ideal Gas Law, to find out the volume

P. V = n . R . T

2 atm . V = 0.2 mol . 0.08206L atm/K mol . 273K

V = (0.2 mol . 0.08206L atm/K mol . 273K ) / 2 atm

V = 2.24 L

4 0

3 years ago

The half life of plutonium-239 (239pu, pu-239) is 24,100 years. How much plutonium will remain after 1000 years if the initial a

Anestetic [448]

The mass of plutonium that will remain after 1000 years if the initial amount is 5 g when the half life of plutonium-239 (239pu, pu-239) is 24,100 years is 2.5 g

The equation is Mr=Mi(1/2)^n

where n is the number of half-lives

Mr is the mass remaining after n half lives

Mi is the initial mass of the sample

To find n, the number of half-lives, divide the total time 1000 by the time of the half-life(24,100)

n=1000/24100=0.0414

So Mr=5x(1/2)^1=2.5 g

The mass remaining is 2.5 g

The half life is the time in which the concentration of a substance decreases to half of the initial value.

Learn more about half life at:

brainly.com/question/24710827

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8 0

1 year ago

At stp what is the volume of 5.35 moles of methane ch4​

At stp what is the volume of 5.35 moles of methane ch4