Please help i will mark brainliest <33
1 answer:
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By definition, the average change of rate is given by:
We will calculate AVR for each of the functions.
We have then:
f(x) = x^2 + 3x interval: [-2, 3]:
f(x) = 3x - 8 interval: [4, 5]:
f(x) = x^2 - 2x interval: [-3, 4]
f(x) = x^2 - 5 interval: [-1, 1]
Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x
We will calculate AVR for each of the functions.
We have then:
f(x) = x^2 + 3x interval: [-2, 3]:
f(x) = 3x - 8 interval: [4, 5]:
f(x) = x^2 - 2x interval: [-3, 4]
f(x) = x^2 - 5 interval: [-1, 1]
Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x
Answer:
1. So, it's basically y=mx + b, you put the b first like y= 2/3x -1, and the b is negative, so you go down on the y-axis one time and the 2/3x is rise over run 2 is the rise and 3 is the run.
for y=-x -4 you put a denominator for -x like -1/1x you keep the denominator positive.
2. If the 2x is in the incorrect spot you put it on the other side and it's a positive, so you put is as a negative on the other side, so you're left with
-y=-2x-1, but you can't have a sign on them, so you divide it with -1 and on the other side as well, so it comes down to y=2x+1 and if the x doesn't have a denominator you add a one to it, like this y=2/1x+1 and you put the 1 on the y-axis and its a positive so you go up one time and the rise or run is 2/1, so you start at 1 on the y-axis and you rise 2 times, so 3-axis and run 1 time and it's 1-axis.
For the last one ill do it on paper.
