Was .08 off its 4.08 like that guy explained
Complete Question
A sample of aluminum, which has a specific heat capacity of 0.897 JB loc ! is put into a calorimeter (see sketch at right) that contains 200.0 g of water. The aluminum sample starts off at 85.6 °C and the temperature of the water starts off at 16.0 °C. When the temperature of the water stops changing it's 20.1 °C. The pressure remains constant at 1 atm. Calculate the mass of the aluminum sample.
Answer:

Explanation:
From the question we are told that:
Heat Capacity 
Mass of water 
Initial Temperature of Aluminium 
Initial Temperature of Water 
Final Temperature of Water 
Generally
Heat loss=Heat Gain
Therefore


Sissy imposter among us haha
On the basis of the given data:
Volume (V) is 37.5 L
Temperature (T) is 307 K
Pressure (P) is 1.25 atm
In order to calculate the number of moles, the formula to be used is PV = nRT, Here R is 0.0821 Latm/mol/K
n = PV / RT
n = 1.25 atm × 37.5 L / 0.0821 Latm/mol/K × 307 K
n = 1.85 mol