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frez [133]
3 years ago
10

A block is pulled across a table by a constant force of 9.20 N. If the mass of the block is 2.30kg, how fast will the block be m

oving after 2.00 seconds? Assume negligible friction.
Physics
1 answer:
kaheart [24]3 years ago
5 0

Answer:

8\:\text{m/s}

Explanation:

From Newton's 2nd Law, we have \Sigma F=ma. Using this, we can find the acceleration of the object:

9.20=2.30a,\\a=\frac{9.20}{2.30}=4\:\mathrm{m/s^2}.

Now that we've found the block's acceleration, we can use the following kinematics equation to find its final velocity after 2 seconds:

v_f=v_i+at,\\v_f=0+4(2),\\v_f=\boxed{8\:\text{m/s}}

*Assumption: The block is initially at rest and has a initial velocity of zero. Otherwise, the question is unsolvable.

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