Question

A block is pulled across a table by a constant force of 9.20 N. If the mass of the block is 2.30kg, how fast will the block be moving after 2.00 seconds? Assume negligible friction.

Answer 1

Answer:

$8\:\text{m/s}$

Explanation:

From Newton's 2nd Law, we have $\Sigma F=ma$. Using this, we can find the acceleration of the object:

$9.20=2.30a,\\a=\frac{9.20}{2.30}=4\:\mathrm{m/s^2}$.

Now that we've found the block's acceleration, we can use the following kinematics equation to find its final velocity after 2 seconds:

$v_f=v_i+at,\\v_f=0+4(2),\\v_f=\boxed{8\:\text{m/s}}$

*Assumption: The block is initially at rest and has a initial velocity of zero. Otherwise, the question is unsolvable.