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solniwko [45]
1 year ago
14

A diverging lens has a focal length of magnitude 21.8 cm.

Physics
1 answer:
Reil [10]1 year ago
3 0

A diverging lens has a focal length of magnitude 21.8 cm and the images are located behind the lens.

(a) u = -10.9 cm

1/v= 1/10.9 - 1/21.9

v= 21.8cm

Behind the lens.

(b) 1. Virtual

   2. Virtual

   3. Real

(c) m = v/u

1. Erect/ Upright

2. Upright

3. Inverted

(d) m = v/u

1. m = -43.6/-43.6 = 1. Magnification = 1.

2. infinity.

3. m = 21.8 / -10.9 = -2. Magnification = -2.

Therefore, these are the answers for above given question.

To know more about diverging lens visit

brainly.com/question/3140453

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xxTIMURxx [149]

The acceleration of a rocket engine is given here, and after 50 seconds of flight, the engine fails, and we must determine the altitude of the rocket at the time the engine fails.  Because the rocket starts from rest, the time taken is 50 seconds, the initial velocity is zero, and the acceleration is 22.9 meters per second square. So we use the kinamatics equation s equal to v. I t plus half 8 square. There is no acceleration at the start. 22.9 and t is 50 seconds, so displacement 2.86 times 10 to the power 4 is met. This is the rocket's displacement in 50 seconds, so this is the rocket's altitude when the engine fails.

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Hence, There is no acceleration at the start. 22. This is the rocket's displacement in 50 seconds, so this is the rocket's altitude when the engine fails.

To know more about Accelerate refer to:

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3 0
1 year ago
The orbits of all the planets in the solar system are slightly elliptical with the exception of _______.
aksik [14]

Answer:

There is no exception to this. all planets have some eccentricity. it is physically impossible to have an orbit without any eccentricity. However, venus's orbit has the lowest (0.007) eccentricity (closest to circular) so that could be your answer.

Mercury's orbit's eccentricity 0.2

Venus's orbit's eccentricity 0.007 (this is the lowest so it may be your answer)

Earth's orbit's eccentricity 0.0167

Mars's orbit's eccentricity 0.0934

Jupiter's orbit's eccentricity 0.0489

Saturn's orbit's eccentricity 0.0565

Neptune's orbit's eccentricity 0.009

Uranus's (yur,in,iss) orbit's eccentricity 0.0457

Pluto's (not really a planet) orbit's eccentricity 0.2444 (very high)

hope it helped.

Wbob3914

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3 years ago
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the correct answer is 0

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storchak [24]

Answer:

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Explanation:

Absolute magnitude is how bright the star is from a distance of 10 parsecs. Apparent magnitude is how bright the star appears from Earth, which can vary, because some stars may be farther or closer away. Age and size are not very accurate either. For example, at the end of their lifetimes, very big start may explode in a violent and bright supernova, and outshine the stars near them. As for size, as many stars several times smaller than the sun shine much brighter than it, making it inaccurate.

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