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Oksanka [162]
2 years ago
10

If the atmospheric pressure is 15 lb/in, what is the corresponding downward force on the top of a horizontal square area 5 inche

s on each side ?
Physics
1 answer:
mr Goodwill [35]2 years ago
3 0

The corresponding downward force on the top of a horizontal square is 375 lb.in

<h3>What is pressure?</h3>

The pressure is the amount of force applied per unit area. It is represented as

Pressure p = Force/Area

If the atmospheric pressure is 15 lb/in and  area 5 inches on each side is

A = 5² = 25  in²

The force applied is

15 lb/in = F /25 in²

F = 375 lb.in

Hence, the corresponding downward force on the top of a horizontal square is 375 lb.in

Learn more about pressure.

brainly.com/question/12971272

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Answer:

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Explanation:

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3 years ago
Starting from rest, a person runs with a constant acceleration, traveling 40 meters in 10 seconds. What is their final velocity?
Assoli18 [71]

Answer:

Final velocity v = 8.944 m/sec

Explanation:

We have given distance S = 40 meters

Time t = 10 sec

As it starts from rest so initial velocity u = 0

From second equation of motion s=ut+\frac{1}{2}at^2

40=0\times 10+\frac{1}{2}a10^2

a=0.8944m/sec^2

Now from first equation of motion v=u+at, here v is final velocity, u is initial velocity, a is acceleration and t is time

So v=u+at=0+0.8944\times 10=8.944m/sec

6 0
3 years ago
A 1400-kg car is traveling with a speed of 17.7 m/s. What is the magnitude of the horizontal net force that is required to bring
AleksandrR [38]

Answer:

The magnitude of the horizontal net force is 13244 N.

Explanation:

Given that,

Mass of car = 1400 kg

Speed = 17.7 m/s

Distance = 33.1 m

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Using equation of motion

v^2-u^2=2as

Where, u = initial velocity

v = final velocity

s = distance

Put the value in the equation

0-(17.7)^2=2a\times 33.1

a=\dfrac{-(17.7)^2}{33.1}

a=-9.46\ m/s^2

Negative sign shows the deceleration.

We need to calculate the net force

Using newton's formula

F = ma

F =1400\times(-9.46)

F=-13244\ N

Negative sign shows the force is opposite the direction of the motion.

The magnitude of the force is

|F| =13244\ N

Hence,  The magnitude of the horizontal net force is 13244 N.

5 0
3 years ago
The figure shows three displacement vectors, which are
aleksley [76]

Answer:

the correct answer is D

Explanation:

In this exercise, the vectors are in the same west-east direction, so we can assume that the positive direction is east and perform the algebraic sum.

       R = δ + ε

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       δ = 2.0 m

       ε = 7.0 m

the positive sign indicates that it is heading east

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        R = 9.0 m

the direction is east

the correct answer is D

8 0
3 years ago
A person is walking briskly in a straight line. The figure shows a graph of the person’s position x as a function of time t. Wha
Nina [5.8K]

The average velocity over the interval 6\le t\le 10 is

\dfrac{x(10)-x(6)}{10\,\mathrm s-6\,\mathrm s}=\dfrac{6\,\mathrm m-2.67\,\mathrm m}{4\,\mathrm s}=0.8325\,\dfrac{\mathrm m}{\mathrm s}

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7 0
3 years ago
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