Answer:
I'm not sure
Explanation:
I have had that question to Uchida c r go crew in to go be
Answer:
Final velocity v = 8.944 m/sec
Explanation:
We have given distance S = 40 meters
Time t = 10 sec
As it starts from rest so initial velocity u = 0
From second equation of motion 


Now from first equation of motion
, here v is final velocity, u is initial velocity, a is acceleration and t is time
So 
Answer:
The magnitude of the horizontal net force is 13244 N.
Explanation:
Given that,
Mass of car = 1400 kg
Speed = 17.7 m/s
Distance = 33.1 m
We need to calculate the acceleration
Using equation of motion

Where, u = initial velocity
v = final velocity
s = distance
Put the value in the equation



Negative sign shows the deceleration.
We need to calculate the net force
Using newton's formula



Negative sign shows the force is opposite the direction of the motion.
The magnitude of the force is

Hence, The magnitude of the horizontal net force is 13244 N.
Answer:
the correct answer is D
Explanation:
In this exercise, the vectors are in the same west-east direction, so we can assume that the positive direction is east and perform the algebraic sum.
R = δ + ε
where
δ = 2.0 m
ε = 7.0 m
the positive sign indicates that it is heading east
R = 2.0 + 7.0
R = 9.0 m
the direction is east
the correct answer is D