How does the direction of friction relate to the direction of motion

1 answer:

5 0

It reacts to the motion. If the mass hanging from the pulley was overwhelmingly heavier than the mass on the ramp, it'll obviously pull the ramp mass up and thus friction would be trying to oppose this and vice versa.

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A proton is released from rest at the origin in a uniform electric field that is directed in the positive x direction with magni

Vika [28.1K]

Explanation:

It is given that,

Electric field, $E=950\ N/C$

We need to find the change in the electric potential energy of the proton-field system when the proton travels to x = 2.5 m

From the conservation of energy, the loss in potential energy is equal to the gain in kinetic energy and kinetic energy is is equal to the work done.

$W=F\times x$

$W=q\times E\times x$

$W=1.6\times 10^{-19}\times 950\times 2.5$

$W=3.8\times 10^{-16}\ J$

So, the change in electric potential energy of the proton field system is $3.8\times 10^{-16}\ J$ . Hence, this is the required solution.

4 0

3 years ago

Would you expect to find a high or low level of resistance in a copper wire and why?

marysya [2.9K]

Low. Copper has relatively high conductivity.

4 0

4 years ago

The electric potential at a certain distance from a point charge can be represented by V. What is the value of the electric pote

Maksim231197 [3]

Answer:

b. At twice the distance, the electric potential is V/2

Explanation:

Electric potential

Is the amount of work needed to move a unit charge from a reference point (usually a point at infinity) without producing acceleration.

The electric potential due to a point charge q at a distance r is given by

$\displaystyle V=K\frac{q}{r}$

Where K is the Coulomb's constant. If we know the electric potential at a certain distance is V, if the distance is changed to 2r, then the new potential is

$\displaystyle V'=K\frac{q}{2r}=\frac{1}{2}K\frac{q}{r}=\frac{1}{2}V$