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zzz [600]
3 years ago
10

I REALLY NEED HELP ASAP PLEASE EXPLAIN WILL GIVE BRAINLIEST!

Mathematics
1 answer:
Irina18 [472]3 years ago
3 0

Answer:

(I attached an image of the graphed lines)

Step-by-step explanation:

First, we need to graph the original function:

  1. The given equation is written in y=mx+b form, in which m is the slope and b is the y-intercept, or where the line crosses through the y axis. This means the slope is \frac{2}{1} and the y-intercept is -4.

Next, we need to find the inverse of the function and graph that as well:

  1. First, change f(x) in the given equation to y. These mean the same thing, it just makes it easier to work with.
  2. Swap the places of x and y. Then, the rest of the steps are essentially just isolating the variable y.
  3. Add 4 to both sides of the equation to cancel out the -4 (You will end up with -2y = x + 4)
  4. Divide both sides of the equation by -2 to isolate y (You will end up with y = (x/2) + 2)

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Simplify the following surds :<br><br> 1) 2√21 × √27 ÷ √343<br> 2) 7√5 × √125 ÷ 2√27
ludmilkaskok [199]

Answer:

1) \frac{18}{7}

2) \frac{175\sqrt{3}}{18}

Step-by-step explanation:

* Lets explain how to simplify a square root

1)

∵ 2\sqrt{21} × \sqrt{27} ÷ \sqrt{343}

∵ \sqrt{21}=\sqrt{3} × \sqrt{7}

∴ 2\sqrt{21} = 2\sqrt{3} × \sqrt{7}

∵ \sqrt{27} = \sqrt{3} × \sqrt{3} × \sqrt{3}

∵ \sqrt{3} × \sqrt{3} = 3

∴ \sqrt{27} = 3\sqrt{3}

∴ 2\sqrt{21} × \sqrt{27} =

  2\sqrt{3} × \sqrt{7} × 3\sqrt{3}

∵ \sqrt{3} × \sqrt{3} = 3

∵ 2 × 3 × 3 = 18

∴ 2\sqrt{21} × \sqrt{27} = 18\sqrt{7}

∵ \sqrt{343} = \sqrt{7} × \sqrt{7} × \sqrt{7}

∵ \sqrt{7} × \sqrt{7} = 7

∴ \sqrt{343} = 7\sqrt{7}

∵ 2\sqrt{21} × \sqrt{27} ÷ \sqrt{343} =

  18\sqrt{7} ÷ 7\sqrt{7}

∵ \sqrt{7} ÷ \sqrt{7} = 1

∴ 2\sqrt{21} × \sqrt{27} ÷ \sqrt{343} =

  \frac{18}{7}

2)

∵ 7\sqrt{5} × \sqrt{125} ÷ 2\sqrt{27}  

∵ \sqrt{125} = \sqrt{5} × \sqrt{5} × \sqrt{5}

∵ \sqrt{5} × \sqrt{5} = 5

∴ \sqrt{125} = 5\sqrt{5}

∴ 7\sqrt{5} × \sqrt{125} =

  7\sqrt{5} × 5\sqrt{5}

∵ \sqrt{5} × \sqrt{5} = 5

∴ 7\sqrt{5} × \sqrt{125} = 7 × 5 × 5 = 175

∵ 2\sqrt{27} = 2\sqrt{3} × \sqrt{3} × \sqrt{3}

∵ \sqrt{3} × \sqrt{3} = 3

∴ 2\sqrt{27} = 6\sqrt{3}

∴ 7\sqrt{5} × \sqrt{125} ÷ 2\sqrt{27} =

  175 ÷ 6\sqrt{3} = \frac{175}{6\sqrt{3}}

∵ \frac{175}{6\sqrt{3}} not in the simplest form because

  the denominator has square root

∴ Multiply up and down by \sqrt{3}

∴  \frac{175}{6\sqrt{3}} = \frac{175\sqrt{3}}{6\sqrt{3}*\sqrt{3}}

∴  \frac{175}{6\sqrt{3}} = \frac{175\sqrt{3}}{18}

∴ 7\sqrt{5} × \sqrt{125} ÷ 2\sqrt{27} =

  \frac{175\sqrt{3}}{18}

7 0
3 years ago
Our material handlers make $15 per hour, and it takes them about 15 minutes to complete this process. How much is our handling c
Arlecino [84]

Answer: $3.75

Step-by-step explanation: $15x15=225/60= 3.75

5 0
3 years ago
Answer for Answer Help me and ill help you.. Ill also mark you brilliant.. I really need help please!!
mixer [17]

Answer:

- The point (7,0) is an x-intercept of the function

- The point (-3,0) is an x-intercept of the function

- As x -> - infinity, f(x) -> + infinity, and ss x -> infinity, f(x) -> + infinity

Step-by-step explanation:

4 0
3 years ago
Which inequality models this problem?
Dahasolnce [82]

850w \geqslant 7500 + 300w

6 0
3 years ago
Read 2 more answers
What is the power of the variable in a constant term?
luda_lava [24]

Answer:

<h2><em><u>C</u></em><em><u>.</u></em><em><u> </u></em><em><u>0</u></em><em><u> </u></em></h2>

Step-by-step explanation:

As,

In a constant term the power of the variable is zero, so it's degree is 0.

<em><u>Eg</u></em><em><u>:</u></em>

4 {a}^{0}

<em><u>Since</u></em><em><u>,</u></em>

<em><u>{x}^{0}  = 1</u></em>

<em><u>Hence</u></em><em><u>,</u></em>

4 × 1 = 4

<em><u>Here, The value remains unchanged hence it is the constant variable. </u></em>

3 0
3 years ago
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