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3 years ago

Analyze the reaction to determine whether the

Chemistry

2 answers:

ser-zykov [4K]3 years ago

7 0

Answer:

The reaction is exothermic. A net release of energy from the reacting

substances into the surroundings makes

this an exothermic reaction. The equation shows that 891 kJ of energy

are released as a product. The graph shows that the reactants have

greater potential energy than the products.

This means the difference in energy is

released to the surroundings.

Explanation:

I got it correct on Edg. :-)

Bumek [7]3 years ago

6 0

Answer: Exothermic

Explanation: Looking at the graph, you see that the reaction started with more energy than it ended with, meaning it gave out its energy over the course of the reaction. This is also confirmed by the reaction equation, which shows the energy (891 kJ) on the right side of the equation.

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Aluminum chloride can be formed from its elements:

saul85 [17]

Answer: The $\Deltas H^o_{formation}$ for the reaction is -1406.8 kJ.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical reaction for the formation reaction of $AlCl_3$ is:

$2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3 (s)$ $\Delta H^o_{formation}=?$

The intermediate balanced chemical reaction are:

(1) $HCl(g)\rightarrow HCl(aq.)$ $\Delta H_1=-74.8kJ$ ( × 6)

(2) $H_2(g)+Cl_2(g)\rightarrow 2HCl(g)$ $\Delta H_2=-185kJ$ ( × 3)

(3) $AlCl_3(aq.)\rightarrow AlCl_3(s)$ $\Delta H_3=+323kJ$ ( × 2)

(4) $2Al(s)+6HCl(aq.)\rightarrow 2AlCl_3(aq.)+3H_2(g)$ $\Delta H_4=-1049kJ$

The expression for enthalpy of formation of $AlCl_3$ is,

$\Delta H^o_{formation}=[6\times \Delta H_1]+[3\times \Delta H_2]+[2\times \Delta H_3]+[1\times \Delta H_4]$

Putting values in above equation, we get:

$\Delta H^o_{formation}=[(-74.8\times 6)+(-185\times 3)+(323\times 2)+(-1049\times 1)]=-1406.8kJ$

Hence, the $\Deltas H^o_{formation}$ for the reaction is -1406.8 kJ.

6 0

3 years ago

If a drug caused a sudden release of large amounts of calcium in skeletal muscle, from which structure would the calcium come?

lawyer [7]

Sarcoplasmic reticulum

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3 years ago

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What type of stress results when two plates push against one another?

Natasha2012 [34]

When two plates push against each other shear stress will happem because they move in opposite directions. In this case the force of the stress pushes some of the crust in different directions. When this happens, a large part of the crust can break off, which makes the plate size smaller.

3 0

3 years ago

Which provides a baseline for an experimental investigation

Goryan [66]

Answer:

control group

Explanation:

7 0

3 years ago

What is the concentration of a potassium iodate solution after you complete the following porcedure? Pipette 10 mL of a 0.31 M p

zubka84 [21]

Given:

Initial concentration of potassium iodate (KIO3) M1 = 0.31 M

Initial volume of KIO3 (stock solution) V1 = 10 ml

Final volume of KIO3 V2 = 100 ml

To determine:

The final concentration of KIO3 i.e. M2

Explanation:

Use the relation-

M1V1 = M2V2

M2 = M1V1/V2 = 0.31 M * 10 ml/100 ml = 0.031 M

Ans: The concentration of KIO3 after dilution is 0.031 M

4 0

3 years ago