Answer:
x=5 twice
Step-by-step explanation:
x^2-10x+25=0
multiply the coefficient of x^2 and the last term
1X25=25
find two numbers you can multiply to get 25 and add to get -10
-5 + (-5)=-10 the middle term
replace -10x with -5x -5x and solve the equation
x^2-5x-5x+25=0
factorise by grouping
x(x-5)-5(x-5)=0
(x-5)(x-5)=0
Either x-5=0,x=5 or x-5=0,x=5
Therefore x=5 twice.
Answer:
12/11
Step-by-step explanation:
y2-y1/x2-x1
(-4-8)/(-2-9)
B is the answer to your question
So this is going to be alot of writing to show my thinking but ill bold the answer.
1,1
1,2
1,3
1,4
1,5
2,1
2,2
2,3
2,4
2,5
3,1
3,2
3,3
3,4
3,5
4,1
4,2
4,3
4,4
4,5
5,1
5,2
5,3
5,4
5,5
next ill mark all the ones that equal 4 or 8 when added together, with an x
1,1
1,2
x1,3
1,4
1,5
2,1
x2,2
2,3
2,4
2,5
x3,1
3,2
3,3
3,4
x3,5
4,1
4,2
4,3
x4,4
4,5
5,1
5,2
x5,3
5,4
5,5
that is 6 (that equal 4 or 8) out of 25
so your ratio would be 6:19
