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Korolek [52]
3 years ago
9

Jennifer jogged at a rate of 3/5 mile every 6 minutes. what was her jogging rate in miles per hour

Mathematics
1 answer:
alexgriva [62]3 years ago
7 0

Answer:

she jogged for 35 hours

Step-by-step explanation:

6×5 6+5=11 11+6=17 17+6=23 23+6=29 29+6=35

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In the number 8.028 does one 8 have a value of 100 times the other 8 ?
nirvana33 [79]

Answer:

No, The 8 in the ones place of the decimal and the 8 in the thousands. Decimals go by variables of 10 if that makes sense

so hopping from the 8 in the ones place it would go 10, 100,1000.

Therefore the statement is false because the value between the eitghts is not 100 its 1000

6 0
3 years ago
Please please please help me please
Step2247 [10]

Answer:

Each term is a sum of the two previous terms like the fibonacci sequence, but the sum of the two starting terms of the lucas sequence is followed by 2 then 1, rather than 0 then 1 for the fibannaci sequence.

These are integer sequences.

The sum of the two previous terms can be represented by:

fn = fn-1 + fn-2.

These numbers can be obtained by adding the previous corresponding term of the fibonacci sequence by the next corresponding term to get the corresponding number of the lucas sequence.

Ln = { 2 if n = 0

1 if n = 1

Ln-1 + Ln-2 if n > 1

________________

Fn+1 + Fn-1 = Ln

___________________

f(0) = -1

f(1) = 2, f(2) = 1, f(3) = 3, f(4) = 4, f(5) = 7, f(6) = 11

________________________________

f(12) = 199

________

f(12) = f(11) + f(10) = (f(10) + f(9)) + (f(9) + f(8)) = .....

given f(n) = f(n-1) + f(n-2)

____________________

f(12) = f(1) + f(2) = f(2) + f(3) = f(3) + f(4) =

f(4) + f(5) = f(5) + f(6) = f(6) + f(7) =

f(7) + f(8) = f(8) + f(9) = f(9) + f(10) =

f(10) + f(11) = f(12) →

f(12) = 2 + 1 = 1 + [3] = 3 + [4] = 4 + [7] =

7 + [11] = 11 + [18] = 18 + [29] = 29 + [47] =

47 + [76] = 76 + [123] = <u>199</u>

_____________________

Explicit formula

for n is an integer.

Nth term of the lucas sequence.

As you can see, the golden ratio

( 1 + √5 / 2) appears in here.

L(n) = ((1 + √5) / 2)ⁿ⁻¹ + ((1 – √5) / 2)ⁿ⁻¹

6 0
3 years ago
Please help!<br><br> Answers:<br> 15<br> 70<br> 55<br> 105
yulyashka [42]
Equation:
3x + 10 = (180 - (5x - 5) ) \div 2 \\ ... \\ x = 15 \\
3x+10 = 45+10 = 55
The answer is 55 because this is a isosceles triangle.
7 0
3 years ago
How many different 10 person committees can be selected from a pool of 23 people?
Salsk061 [2.6K]

We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.

We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.

Formula for combination:

C(n,r)=\dfrac{n!}{(n-r)!r!}

Where n represents the number of objects/people in the set and r represents the number of objects/people being chosen from the set

There are 23 people in the set and 10 people being chosen from the set

C(23,10)=\dfrac{23!}{(23-10)!10!}

=\dfrac{23!}{13!\times10!}

Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

=1,144,066

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!

~ Padoru

4 0
3 years ago
Read 2 more answers
Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from
Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that P = 3000, r = 0.16, n = 1

So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 3000(1 + \frac{0.16}{1})^{t}

A(t) = 3000(1.16)^{t}

(a) Find the amount in the account at the end of 1 year.

This is A(1).

A(t) = 3000(1.16)^{t}

A(1) = 3000(1.16)^{1} = 3480

(b) Find the amount in the account at the end of 2 years.

This is A(2).

A(2) = 3000(1.16)^{2} = 4036.8

4 0
3 years ago
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