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Korolek [52]
3 years ago
9

Jennifer jogged at a rate of 3/5 mile every 6 minutes. what was her jogging rate in miles per hour

Mathematics
1 answer:
alexgriva [62]3 years ago
7 0

Answer:

she jogged for 35 hours

Step-by-step explanation:

6×5 6+5=11 11+6=17 17+6=23 23+6=29 29+6=35

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Felix Carson is employed at a high school. He has family medical coverage through the school's
Lady bird [3.3K]

Answer:

$56.77 each week

Step-by-step explanation:

He pays for 30% of 9867 per year.

9867*0.3=2960.1

Divide the answer by number of weeks in a year.

= $56.7689

Round.

4 0
3 years ago
What is the center and radius of the equation (x-8)^2 +(y+6)^2=13
tatyana61 [14]

Answer:

see explanation

Step-by-step explanation:

the equation of a circle in standard form is

(x - a)² + (y - b)² = r²

where (a, b) are the coordinates of the centre and r is the radius

(x - 8)² + (y + 6)² = 13 is in this form

with centre = (8, - 6) and r = \sqrt{13}



6 0
3 years ago
A circle is defined by the equation x2 + y2 + 8x + 22y + 37 = 0. What are the coordinates for the center of the circle and the l
inn [45]
We can say that:
8x = -2ax
8 = -2a
a = -4

22y = - 2by
22 = -2b
b = -11

37 = a² + b² - r²
37 = (-4)² + (-11)² - r²
r² = 16 + 121 - 37
r² = 100
r = 10

With all this information, we can say that:
The center of the circle is: (-4 ; -11)
and the radius of the circle is r = 10

P.S:
(a - x)² + (b-y)² = r²
a² - 2ax + x² + b² -2by + y² - r² = 0
x² + y² -2ax - 2by + a² + b² - r² = 0

6 0
3 years ago
N is an integer and - 2<n+3<4, write down the possible values of n from smallest to largest​
Korolek [52]

Answer:

- 4, - 3, - 2, - 1, 0

Step-by-step explanation:

Given

- 2 < n + 3 < 4 ( subtract 3 from each interval )

- 5 < n < 1

This indicates that n ≠ - 5, 1 but all values in between, that is

n = - 4, - 3, - 2, - 1, 0 ← possible values of n

4 0
3 years ago
Is this set of ordered pairs a function ? (1,9) (0,8) (3,0) (4,9) (7,7).
AURORKA [14]

Answer:

It is not a function because the output of 9 repeats.

(1,9) (4,9)

:D

3 0
3 years ago
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