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Papessa [141]
3 years ago
6

PLEASE HELP

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
7 0
The sum of exterior angles in total: 360 degrees

6th angle = 78+50+89+37+65= 319
Then 360-319= 41 degrees
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Which function has the greatest constant of variation? A x 8 9 10 11 y 20 22.5 25 27.5 B x 1 2 3 4 y 3.2 6.4 9.6 12.8
Lina20 [59]

Answer : B x 1 2 3 4 y 3.2 6.4 9.6 12.8

WE analyze the first option A

x -- y -- Difference

8 -- 20

9 -- 22.5 -- 2.5

10 -- 25 -- 2.5

11 -- 27.5 -- 2.5

From the first function we can see there is a constant difference of 2.5.

We analyze the second option B

x -- y -- Difference

1 -- 3.2

2 -- 6.4 -- 3.2

3 -- 9.6 -- 3.2

48 -- 12.8 -- 3.2

From the second function we can see there is a constant difference of 3.2

3.2 is the greatest

So second function B has the greatest constant of variation.

4 0
3 years ago
Read 2 more answers
Here’s the answer you need to know
vovikov84 [41]
Thank you sooo much Maddi441
8 0
3 years ago
12x - 3x + 4 = 5x - 16<br> Please show me how you got it!
FinnZ [79.3K]

Answer:

x = -5

Step-by-step explanation:

Combine them like terms,then you subtract 4 from both sides,and then Simplify

8 0
3 years ago
Read 2 more answers
1/3 as a decimal and percent please answer !!
Alborosie

Answer:

decimal: .3333(repeatin)

percent:33.333333...%

Step-by-step explanation:

hope this helpss

have a good night

nd good luck w thiss

8 0
3 years ago
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Write the following sum using summation notation -2/5+3/6-4/7........11/14
horrorfan [7]

Answer:

\sum_{n=1}^{10}(-1)^n\left ( \frac{n+1}{n+4} \right )

Step-by-step explanation:

Given: \frac{-2}{5}+\frac{3}{6}-\frac{4}{7}+...+\frac{11}{14}

To write: the given expression using summation notation

Solution:

Summation notation helps to write a long sum as a single expression.

In the summation notation, the variable \sum is called the index of summation.

Let x_1,x_2,x_3,...,x_n denote a set of n numbers.

Then in summation notation,

x_1+x_2+x_3+...+x_n=\sum_{i=1}^{n}x_i

\frac{-2}{5}=(-1)^1\left ( \frac{1+1}{1+4} \right )\\\frac{3}{6}=(-1)^2\left ( \frac{2+1}{2+4} \right )\\\frac{-4}{7}=(-1)^3\left ( \frac{3+1}{3+4} \right )\\.\\.\\.\\\frac{11}{14}=(-1)^10\left ( \frac{10+1}{10+4} \right )\\\therefore \frac{-2}{5}+\frac{3}{6}-\frac{4}{7}+...+\frac{11}{14}=\sum_{n=1}^{10}(-1)^n\left ( \frac{n+1}{n+4} \right )

3 0
3 years ago
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