The two inequalities are :
option B and option C
Explanation:
Daniel moves no more than 30 of his sheep and goats into another field. This means the summation of sheep and goats will be at maximum 30.
that is why it is 
And more than 7 of his animals are sheep means sheep are greater than 7. that is why = 
Answer:
x³/4z²
Step-by-step explanation:
Invert and multiply:
48x^5y²/12z^5 x z³/16x²y²=
(48x^5y²)(z³)/(16x²y²)(12z^5)
the y² cancel out
48÷16=3 (on top)
x^5÷x²=x³
12z^5/z³=z²(on bottom)
This leaves a 3x³ on top and 12z² on the bottom. 3÷12=4 (on bottom):
3x³/12z²
x³/4z²
Answer:
y = - 9, y = 3
Step-by-step explanation:
Calculate distance d using the distance formula
d = 
with (x₁, y₁ ) = (2, - 3) and (x₂, y₂ ) = (10, y)
d = 
= 
Given distance between points is 10, then
= 10 ( square both sides )
64 + (y + 3)² = 100 ( subtract 64 from both sides )
(y + 3)² = 36 ( take the square root of both sides )
y + 3 = ±
= ± 6 ( subtract 3 from both sides )
y = - 3 ± 6 , thus
y = - 3 - 6 = - 9
y = - 3 + 6 = 3