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VMariaS [17]
3 years ago
10

A ball is thrown straight up from the top of a building that is 280 feet high with an initial velocity of 48 ft/s. The height of

the object can be modeled by the equation s(t)=−16t2+48t+280.
In two or more complete sentences explain how to determine the time(s) the ball is higher than the building in interval notation. Then, determine the time.​
Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0

Answer:

i hope it helpful

thank you

Alex3 years ago
7 0

Answer:

Answer in interval notation is (3, 5.94].

Step-by-step explanation:

First find the time that the ball is level with the top of the building on its descent. You can do this by solving 280 = -16^2 + 48t + 280 for t. This gives t = 3 seconds .

Then when the ball reaches the ground the time t is obtained by solving 0 = -16t^2 + 48t + 280 This gives t = 5.94

seconds.

Answer in interval notation is (3, 5.94].

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The Laplace of the given equation is y=-\frac{15e^2}{8}e^{2t}+\left(-3e^2+\frac{15e^2}{4}\right)e^{2t}t+\frac{e^2t^4}{4}+e^2t^3+\frac{9e^2t^2}{4}+3e^2t+\frac{15e^2}{8}.

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brainly.com/question/17062586

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Step-by-step explanation:

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