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VMariaS [17]
3 years ago
10

A ball is thrown straight up from the top of a building that is 280 feet high with an initial velocity of 48 ft/s. The height of

the object can be modeled by the equation s(t)=−16t2+48t+280.
In two or more complete sentences explain how to determine the time(s) the ball is higher than the building in interval notation. Then, determine the time.​
Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0

Answer:

i hope it helpful

thank you

Alex3 years ago
7 0

Answer:

Answer in interval notation is (3, 5.94].

Step-by-step explanation:

First find the time that the ball is level with the top of the building on its descent. You can do this by solving 280 = -16^2 + 48t + 280 for t. This gives t = 3 seconds .

Then when the ball reaches the ground the time t is obtained by solving 0 = -16t^2 + 48t + 280 This gives t = 5.94

seconds.

Answer in interval notation is (3, 5.94].

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Answer:

The  confidence interval is  0.304 <  p  < 0.324

Step-by-step explanation:

From the question we are told

      The sample proportion \r p  =  0.314

      The margin of error  is E =  0.01

The confidence interval for  p is mathematically represented as

       \r p -  E  <  p  < \r p + E

=>    0.314 -  0.01  <  p  < 0.314 +  0.01

=>   0.304 <  p  < 0.324

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5 0
3 years ago
Consider the line y=5x -3 Find the equation of the line that is patellar to this line and passes through the point (-8, -3) Cons
Lynna [10]

Answer:

The equation of the line that is parallel to given line and passes through the point (-8, -3) is: y = 5x+37

Step-by-step explanation:

Given equation of line is:

y=5x-3

The general form of equation of line in slope-intercept form is written as:

y = mx+b

Here m(co-efficient of x) is the slope of the line and b is the y-intercept.

Comparing the given equation with the general form we get

m = 5

Two parallel lines have same slope so the slope of any line parallel to given line will also be 5.

Let m1 be the slope of required line parallel to y=5x-3

Then m1=5

Putting in general form

y = m_1x+b

y=5x+b

To find the value of b(y-intercept) the given point has to be put in the equation from which the line passes.

The point is (-8,-3)

-3 = 5(-8)+b\\-3 = -40+b\\b = -3+40\\b = 37

Putting the value of b and m1, we get

y = 5x+37

Hence,

The equation of the line that is parallel to given line and passes through the point (-8, -3) is: y = 5x+37

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Answer:

Equivalent fractions

Step-by-step explanation:

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