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notsponge [240]
4 years ago
8

Calculate the minimum amount of energy, in joules, required to completely melt 145 g of silver initially at 22.0°C. The melting

point of silver is at 962°C. Its specific heat capacity is 236 J/kg·K and its latent heat of fusion is 105 kJ/kg.
Physics
1 answer:
Tcecarenko [31]4 years ago
6 0

Answer:

47391.8 J

Explanation:

Q = m c Δt

For melting, Δt = (962-22)°C

Heat required to attain melting point = 145 x 10 ⁻³ x 236 x 940 =

= 32166.8 J

Heat required to melt at melting point = m L , L is latent heat of fusion.

= 145 x 10⁻³ x 105 x 10³ = 15225 J

Total energy required = 47391.8 J

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5 0
3 years ago
Can someone please help me ASAP
Serggg [28]

Answer:

distance = 6.1022 x10^16[m]

Explanation:

To solve this problem we must use the formula of the average speed which relates distance to time, so we have

v = distance / time

where:

v = velocity = 3 x 10^8 [m/s]

distance = x [meters]

time = 6.45 [light years]

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t = 6.45 [light-years]*365[\frac{days}{1light-year}]*24[\frac{hr}{1day}] *60[\frac{min}{1hr}]*60[\frac{seg}{1min} ] =203407200 [s]

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8 0
3 years ago
A girl with a mass of 27 kg is playing on a swing. There are three main forces
N76 [4]

The tension in the swing's chain at the bottom of the swing is 178.35 N.

The given parameters:

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  • Radius of the circle, r = 4 m

The tension in the swing's chain at the bottom of the swing is calculated as follows;

T = mg + ma_c\\\\ T= mg + \frac{mv^2}{r} \\\\T = (12 \times 9.8) + (\frac{27 \times 3^2}{4} )\\\\T = 117.6 \ N \ + \ 60.75 \ N\\\\T = 178.35 \ N

Thus, the tension in the swing's chain at the bottom of the swing is 178.35 N.

Learn more about tension in vertical circle here: brainly.com/question/19904705

3 0
2 years ago
After a neutral object loses 2 electrons, it will have a
Zepler [3.9K]

Answer:

the measured charge will be -2 elementary charges.

Explanation:

8 0
2 years ago
Read 2 more answers
A gymnast weighs 450 N. She stands on a balance beam of uniform construction which weighs 250 N. The balance beam is 3.0 m long
Damm [24]

Answer:

   x = 9.32 cm

Explanation:

For this exercise we have an applied torque and the bar is in equilibrium, which is why we use the endowment equilibrium equation

Suppose the counterclockwise turn is positive, let's set our reference frame at the left end of the bar

          - W l / 2 - W_{child} x + N₂ l = 0

             x = \frac{-W l/2 + n_2 l}{W_{child}}             1)

now let's use the expression for translational equilibrium

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indicate that N₂ = 4 N₁

we substitute

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           N₁ = ( W + W_{child}) / 5

         

we calculate

           N₁ = (450 + 250) / 5

          N₁ = 140 N

           

we calculate with equation 1

           x = -250 1.50 + 4 140 3) / 140

           x = 9.32 cm

7 0
3 years ago
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