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V125BC [204]
3 years ago
7

That which flows on uniformly, of which a day is a logical portion, is called time. True or False

Physics
2 answers:
Sergeu [11.5K]3 years ago
8 0
The anwser is true because it has to be time
mr_godi [17]3 years ago
3 0
The answer to the statement is true because the day is of the logical proportion it has to be time.
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PLEASE HELP ME WITH THIS ONE QUESTION
Marizza181 [45]

Answer:

c) 2.02 x 10^16 nuclei

Explanation:

The isotope decay of an atom follows the equation:

ln[A] = -kt + ln[A]₀

<em>Where [A] is the amount of the isotope after time t, k is decay constant, [A]₀ is the initial amount of the isotope</em>

[A] = Our incognite

k is constant decay:

k = ln 2 / Half-life

k = ln 2 / 4.96 x 10^3 s

k = 1.40x10⁻⁴s⁻¹

t is time = 1.98 x 10^4 s

[A]₀ = 3.21 x 10^17 nuclei

ln[A] = -1.40x10⁻⁴s⁻¹*1.98 x 10^4 s + ln[3.21 x 10^17 nuclei]

ln[A] = 37.538

[A] = 2.01x10¹⁶ nuclei remain ≈

<h3>c) 2.02 x 10^16 nuclei</h3>
7 0
2 years ago
A bowling ball with a negative initial velocity slows down as it rolls down the lane toward the pins. Is the bowling ballâs acce
stiv31 [10]

Answer:

positive

Explanation:

The ball is rolling down with a negative velocity, but the velocity is slowing down. therefore the velocity must increase in order for the ball to slow down.

For example let the ball's initial velocity be -15 m/s. and it  is slowing down to let's say -13 m/s. Well this means that it's velocity has increase by 2 m/s. So, its acceleration is positive.

5 0
3 years ago
A 35-mm single lens reflex (SLR) digital camera is using a lens of focal length 35.0 mm to photograph a person who is 1.80 m tal
olganol [36]

Answer:

a) 35.44 mm

b) 17.67 mm

Explanation:

u = Object distance =  3.6 m

v = Image distance

f = Focal length = 35 mm

h_u= Object height = 1.8 m

a) Lens Equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{35}-\frac{1}{3600}\\\Rightarrow \frac{1}{v}=\frac{713}{25200} \\\Rightarrow v=\frac{25200}{713}=35.34\ mm

The CCD sensor is 35.34 mm from the lens

b) Magnification

m=-\frac{v}{u}\\\Rightarrow m=-\frac{35.34}{3600}

m=\frac{h_v}{h_u}\\\Rightarrow -\frac{35.34}{3600}=\frac{h_v}{1800}\\\Rightarrow h_v=-\frac{35.34}{3600}\times 1800=-17.67\ mm

The person appears 17.67 mm tall on the sensor

7 0
2 years ago
Plz and ty ... free points, be nice
harkovskaia [24]

Answer:

Thank you!

Explanation:

5 0
3 years ago
Read 2 more answers
A 3-kg chunk of putty moving at 2 m/s collides with and sticks to a 5-kg bowling ball initially at rest. The bowling ball and pu
Oduvanchick [21]

Answer:

It's Momentum becomes 4

4 0
3 years ago
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