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2 years ago

I need the correct answers

Chemistry

2 answers:

bogdanovich [222]2 years ago

4 0

Answer:

Acids: Tastes Sour

Has a ph less than 7

Base: Bitter

Has a ph greater than 7

slippery

Acid&Base: Conducts electricity

katen-ka-za [31]2 years ago

3 0

Acid
Tastes sour
Has a ph less than 7

Bases
Tastes bitter
Has a ph more than 7
Feels slippery

Acids and bases
Conducts electricity

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Which of the following is the electrical charge on an atom that contains 6 electrons, 3 neutrons, and 4 protons?

Y_Kistochka [10]

Answer:

Its electrical charge is -2.

4 0

3 years ago

Need some help with this problem please!

Tom [10]

Answer:

18 liters

Explanation:

Step 1: Figure out what the formula and what you are dealing with.

- 25 degrees celcius is constant, so it is irrelevant for the mathmatical part.

- P1 = 1 atm

- P2 = 20 atm

- V1 = 360 liters

- V2 = trying to find

Note: remember the original equation is V1/P1 = V2/P2

- Step 2: Rearrange the equation to fit this problem, you should get...

V2 = V1 x P1 / P2

- Step 3: Fill our own numbers in. You should get...

360 L x 1 atm / 20 atm = 18 Liters (do the math)

- Answer = 18 Liters

- Remember to just follow the formula and fill it in with your own numbers.

If you need any more help comment below. I am happy to help anytime.

7 0

3 years ago

Dinitrogen pentoxide is used in the preparation of explosives. If 7.93 mol of

Tpy6a [65]

The volume of O₂ produced: 84.6 L

<h3>Further explanation</h3>

Given

7.93 mol of dinitrogen pentoxide

T = 48 + 273 = 321 K

P = 125 kPa = 1,23365 atm

Required

Volume of O₂

Solution

Decomposition reaction of dinitrogen pentoxide

2N₂O₅(g)→4NO₂(g)+O₂ (g)

From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :

= 0.5 x mol N₂O₅

= 0.5 x 7.93

= 3.965 moles

The volume of O₂ :

$\tt V=\dfrac{nRT}{P}\\\\V=\dfrac{3.965\times 0.082\times 321}{1.23365}\\\\V=84.6~L$

5 0

3 years ago

A 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, what is the volume? *

elena-14-01-66 [18.8K]

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

P1 = initial pressure (kPa)
P2 = final pressure (kPa)
V1 = initial volume (L)
V2 = final volume (L)

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

Learn more about Boyle's law calculations at: brainly.com/question/1437490?referrer=searchResults

3 0

2 years ago

What mass of H₂ is needed to react with 8.75 g of O₂ according to the following equation: O2(g) + H2(g) → H₂O(g)?

FromTheMoon [43]

Explanation:

For reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

The given balanced equation has been:

\rm O_2\;+\;2\;H_2\;\rightarrow\;H_2OO2+2H2→H2O

From the equation, 1 mole of oxygen reacts with 2 mole of hydrogen to give 1 mole of water.

The mass of oxygen has been: 8.75 g,

Moles = \rm \dfrac{weight}{molecular\;weight}molecularweightweight

Moles of oxygen = \rm \dfrac{8.75}{32}328.75

Moles of oxygen = 0.27 mol

Since,

1 mole Oxygen = 2 mole hydrogen

0.21 mol oxygen = 0.54 mol hydrogen

Mass of hydrogen = moles \times× molecular weight

Mass of hydrogen = 0.54 \times× 2

Mass of hydrogen = 1.08 grams.

Thus, for reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

6 0

1 year ago