Answer:
You would have 1.96 moles.
Explanation:
You are given 608 grams of calcium phosphate Ca₃(PO₄)₂.
Molar mass (M) is the amount of mass that a substance contains in one mole. This substance can be an element or a compound.
Since the molar mass of the compound Ca₃(PO₄)₂ is 310 g / mole, and taking into account the definition of molar mass, you can apply the following rule of three: if 310 grams of Ca₃(PO₄)₂ are contained in 1 mole, 608 grams of the compound in how many moles are present?

moles= 1.96
<u><em>You would have 1.96 moles.</em></u>
We have that the original pressure of this gas is mathematically given as
P2=17.854 kPa
<h3>
Boyle's law</h3>
Question Parameters:
AT constant temperature, a gas is compressed from 5.5 L to 1 L.
At 1 L, the pressure of the gas is 98.2 kPa
Generally the equation for Boyle's law is mathematically given as
P1V1=P2V2
Therefore

P2=17.854 kPa
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