Answer:
Lysosomes are predominantly found in eukaryotic animal cells and are responsible for breaking down cellular debris
Explanation:
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In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=

%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
Answer:
-3
Explanation:
The oxidation state or oxidation number of an atom is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.
The complex anion here is [Cr(CN)6]3-.
Now, as the oxidation state of CN or cyanide ligand is -1, and if we suppose the oxidation state of Cr to be 'x', then; x - 6 = -3 (overall charge on the anion),
so x= +3. Hence the oxidation state of Chromium in this complex hexacyanochromium (III) anion comes out to be -3.
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Answer:
kL, dL, mL, pL
Explanation:
pL stands for picoliters. This is equal to 1 × 10⁻¹² (0.000000000001) liters.
mL stands for milliliters. This is equal to 1 × 10⁻³ (0.001) liters.
dL stands for deciliters. This is equal to 1 × 10⁻¹ (0.1) liters.
kL stands for kiloliters. This is equal to 1 × 10³ (1000) liters.