All categories

3 years ago

Is 22.99 mol of Na equal or not equal to Avogadro's number?

Chemistry

1 answer:

Artist 52 [7]3 years ago

3 0

Answer:

It is not equal to Avogadro constant

Explanation:

This is because Avogadro constant refer to the number of molecules or atoms of particles per mile substance and thus is equal to 6.022×10^23 per mile or unit of that substance.

You might be interested in

Please solve this fast pleasee i will make u the brainliest

mote1985 [20]

1. Thermoplastics
2. Thermosetting plastics
4. Nylon
5. Thermoplastics like polythene
6. Thermosetting plastics like melamine
7. Natural
8. Raw
11. Light and durable
13. repeating subunits
14. Naturally from silkworms
15. Thermoplastics
16. Air and water
17. Less-reactive
18. Poly-tetra-fluoroethylene ptfe

3 0

2 years ago

A mileage test is conducted for a new car model. Thirty randomly selected cars are driven for a month and the mileage is measure

Leni [432]

Answer: $(27.81,\ 29.39)$

Explanation:

Given : Sample size : n= 30 , it means it is a large sample (n≥ 30), so we use z-test .

Significance level : $\alpha: 1-0.95=0.05$

Critical value: $z_{\alpha/2}=1.96$

Sample mean : $\overline{x}=28.6$

Standard deviation : $\sigma=2.2$

The formula to find the confidence interval is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

i.e. $28.6\pm (1.96)\dfrac{2.2}{\sqrt{30}}$

i.e. $28.6\pm 0.787259889321$

$\approx28.6\pm 0.79=(28.6-0.79,28.6+0.79)=(27.81,\ 29.39)$

Hence, the 95% confidence interval for the mean mpg in the entire population of that car model = $(27.81,\ 29.39)$

4 0

3 years ago

How many liters of solution can be produced from 2.5 moles of solute if a 2.0 M

Firlakuza [10]

Answer:

The answer is 1.25 L

Explanation:

5 0

2 years ago

Calculate the mass of bromine in 50.0 g of potassium bromide

Elodia [21]

Answer:

6 Percent Composition. 1. Molar Mass of KBr K = 1(39.10) = 39.10 Br =1(79.90) =79.90 MM = 119.0 79.90 g 119.0 g = 0.6714 3. 0.6714 x 50.0g = 33.6 g Br 2.

4 0

2 years ago

When 100 mL of 1.0 M Na3PO4 is mixed with 100 mL of 1.0 M AgNO3, a yellow precipitate forms and [Ag ] becomes negligibly small.

lana [24]

Answer:

$Na3PO4 + 3AgNO3 -------> Ag3PO4 + 3NaNO3$

In which [Ag+] in negligibly small and the concentration of each reactant is 1.0 M

The answer is A) PO43- < NO3- < Na+

Explanation:

Ag+ is removed from the solution just like PO43-, so there are just 2 possible answers at this point: a or b. Then we can notice that Na3PO4 releases 3 moles of Na+ and just 1 mole of NO3-

We have 100mL of each reactant with the same concentration for both (1.0 M) so:

(0.1)(1)(3)= 0.3 mol Na+

(0.1)(1)= 0.1 mol NO3-

so PO43- < NO3- < Na+

5 0

3 years ago