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Viktor [21]
3 years ago
10

Is 22.99 mol of Na equal or not equal to Avogadro's number?

Chemistry
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

It is not equal to Avogadro constant

Explanation:

This is because Avogadro constant refer to the number of molecules or atoms of particles per mile substance and thus is equal to 6.022×10^23 per mile or unit of that substance.

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A mineral ranked higher in the mohs scale is relatively harder than other minerals. Mohs scale lists 10 minerals from the softest to hardest. The hardest mineral is diamon while the softest one is talc. The two minerals compared are scratched with each other. The scratched one is the softer mineral.
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Why does water appear blue?
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Form the complementary solution to the homogeneous equation. yc(t) = Cl [ ] +C2 Construct the (simplest) particular olution of t
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Answer:

See explaination

Explanation:

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6 0
3 years ago
2. How many moles are in 2.8 Liters of CO2 gas?
andrew-mc [135]

Answer:

0.125 moles

Explanation:

2.8 litres is equivalent to 2.8dm³

At STP,

1 mole = 22.4 dm³

x mole = 2.8 dm³

Cross multiply

22.4x = 2.8

Divide both sides by 22.4

x = 2.8/22.4

x = 0.125

4 0
2 years ago
A and b are two gases that are mixed together: 2.50 mol a is mixed with 0.850 mol b. if the final pressure of the mixture is 1.7
USPshnik [31]

Partial pressure of gas A is 1.31 atm and that of gas B is 0.44 atm.

The partial pressure of a gas in a mixture can be calculated as

Pi = Xi x P

Where Pi is the partial pressure; Xi is mole fraction and P is the total pressure of the mixture.

Therefore we have Pa = Xa x P and Pb = Xb x P

Let us find Xa and Xb

Χa = mol a/ total moles = 2.50/(2.50+0.85) = 2.50/3.35 = 0.746

Xb = mol b/total moles = 0.85/(2.50+0.85) = 0.85/3.35 = 0.254

Total pressure P is given as 1.75 atm

Pa = Xa x P = 0.746 x 1.75 = 1.31atm

Partial pressure of gas A is 1.31 atm

Pb = Xb x P = 0.254 x 1.75 = 0.44atm

Partial pressure of gas B is 0.44 atm.

Learn more about Partial pressure here:

brainly.com/question/15302032

#SPJ4

6 0
2 years ago
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