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3 years ago

What is the greatest common factor of 3 and 21x?

Mathematics

1 answer:

Keith_Richards [23]3 years ago

5 0

Answer:

Step-by-step explanation:

3 ÷ 3 = 1

21x ÷ 3 = 7x

There is no other common factor.

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Find the error american car produce 5,650,000 cars each year.In a report,ben wrote that americans made 6,550,000 cars.What mista

Oksanka [162]

Answer:

The error Ben made was writing down 6,550,000 cars rather than 5,650,000 cars in the report.

He can fix it by correcting the wrong numbers.

Step-by-step explanation:

American car produce 5,650,000 cars each year.

When writing a report Ben wrote down that americans produce 6,550,000 cars every year

Therefore the error Ben made in the report was that he mixed the numbers, he ought to have written 5 and 6 as the initial two numbers but rather he wrote the first number as 6 and the second number as 5.

Ben can fix his mistake by correcting the numbers and writing down the correct initial two numbers which are 6 and 5.

Hence, doing this will give him the correct number of cars which is 5,650,000 cars.

8 0

3 years ago

Taj asked 27 classmates whether they know how to write calligraphy .

sukhopar [10]

Answer:

Step-by-step explanation:

what

8 0

3 years ago

Express 83% as a decimal. * 8.3 0.83 83 0.083

svetlana [45]

Answer:

83% would be 0.83 as a decimal

8 0

3 years ago

7y-4y+2= What’s the answer?

Kay [80]

Answer:

3y + 2 =

Step-by-step explanation:

7y - 4y = 3y

3y and 2 are not like terms, so you can't add any further

3 0

2 years ago

Read 2 more answers

A biologist is studying the elk population in a county park. She starts with only 2 elk and observes that the number of elk trip

DochEvi [55]

Answer:

The expression that represents the population of elk is: $\text{elk}(t) = 2*3^t$ . It'll take 6 years for the population to reach 1,458 individuals.

Step-by-step explanation:

Since the number of elks triples every year and starts at $\text{elk}(0) = 2$ , then after the first year the population will be:

$\text{elk}(1) = \text{elk}(0)*3 = 2*3$

While on the second year, it'll be:

$\text{elk}(2) = \text{elk}(1)*3 = 2*3*3 = 2*3^2$

On the third year:

$\text{elk}(3) = \text{elk}(2)*3 = 2*3^2*3 = 2*3^3$

And so on, therefore the expression that describes the population of elk as the years passes is:

$\text{elk}(t) = 2*3^t$

If we want to know the number of years until the population reach 1,458 elk, we need to apply this value to the left side of the equation and solve for t.

$1458 = 2*3^t\\3^t = \frac{1458}{2}\\3^t = 729\\ln(3^t) = ln(729)\\t*ln(3) = ln(729)\\t = \frac{ln(729)}{ln(3)} = 6$

The population will reach 1,458 elk in 6 years.

8 0

3 years ago